Metamath Proof Explorer |
< Previous
Next >
Nearby theorems |
||
Mirrors > Home > MPE Home > Th. List > cdeqab1 | Structured version Visualization version GIF version |
Description: Distribute conditional equality over abstraction. Usage of this theorem is discouraged because it depends on ax-13 2371. (Contributed by Mario Carneiro, 11-Aug-2016.) (New usage is discouraged.) |
Ref | Expression |
---|---|
cdeqnot.1 | ⊢ CondEq(𝑥 = 𝑦 → (𝜑 ↔ 𝜓)) |
Ref | Expression |
---|---|
cdeqab1 | ⊢ CondEq(𝑥 = 𝑦 → {𝑥 ∣ 𝜑} = {𝑦 ∣ 𝜓}) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | nfv 1922 | . . 3 ⊢ Ⅎ𝑦𝜑 | |
2 | nfv 1922 | . . 3 ⊢ Ⅎ𝑥𝜓 | |
3 | cdeqnot.1 | . . . 4 ⊢ CondEq(𝑥 = 𝑦 → (𝜑 ↔ 𝜓)) | |
4 | 3 | cdeqri 3668 | . . 3 ⊢ (𝑥 = 𝑦 → (𝜑 ↔ 𝜓)) |
5 | 1, 2, 4 | cbvab 2807 | . 2 ⊢ {𝑥 ∣ 𝜑} = {𝑦 ∣ 𝜓} |
6 | 5 | cdeqth 3669 | 1 ⊢ CondEq(𝑥 = 𝑦 → {𝑥 ∣ 𝜑} = {𝑦 ∣ 𝜓}) |
Colors of variables: wff setvar class |
Syntax hints: ↔ wb 209 = wceq 1543 {cab 2714 CondEqwcdeq 3665 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1803 ax-4 1817 ax-5 1918 ax-6 1976 ax-7 2018 ax-9 2122 ax-10 2143 ax-11 2160 ax-12 2177 ax-13 2371 ax-ext 2708 |
This theorem depends on definitions: df-bi 210 df-an 400 df-or 848 df-tru 1546 df-ex 1788 df-nf 1792 df-sb 2073 df-clab 2715 df-cleq 2728 df-cdeq 3666 |
This theorem is referenced by: (None) |
Copyright terms: Public domain | W3C validator |