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| Mirrors > Home > MPE Home > Th. List > n0rex | Structured version Visualization version GIF version | ||
| Description: There is an element in a nonempty class which is an element of the class. (Contributed by AV, 17-Dec-2020.) |
| Ref | Expression |
|---|---|
| n0rex | ⊢ (𝐴 ≠ ∅ → ∃𝑥 ∈ 𝐴 𝑥 ∈ 𝐴) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | id 23 | . . . 4 ⊢ (𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐴) | |
| 2 | 1 | ancli 557 | . . 3 ⊢ (𝑥 ∈ 𝐴 → (𝑥 ∈ 𝐴 ∧ 𝑥 ∈ 𝐴)) |
| 3 | 2 | eximi 1865 | . 2 ⊢ (∃𝑥 𝑥 ∈ 𝐴 → ∃𝑥(𝑥 ∈ 𝐴 ∧ 𝑥 ∈ 𝐴)) |
| 4 | n0 4307 | . 2 ⊢ (𝐴 ≠ ∅ ↔ ∃𝑥 𝑥 ∈ 𝐴) | |
| 5 | df-rex 3090 | . 2 ⊢ (∃𝑥 ∈ 𝐴 𝑥 ∈ 𝐴 ↔ ∃𝑥(𝑥 ∈ 𝐴 ∧ 𝑥 ∈ 𝐴)) | |
| 6 | 3, 4, 5 | 3imtr4i 295 | 1 ⊢ (𝐴 ≠ ∅ → ∃𝑥 ∈ 𝐴 𝑥 ∈ 𝐴) |
| Colors of variables: wff setvar class |
| This proof depends on syntax axioms: → wi 4 ∧ wa 400 ∃wex 1809 ∈ wcel 2143 ≠ wne 2958 ∃wrex 3089 ∅c0 4286 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1825 ax-4 1839 ax-5 1940 ax-6 1997 ax-7 2038 ax-9 2153 ax-ext 2735 |
| This proof depends on definitions: df-bi 210 df-an 401 df-tru 1573 df-fal 1583 df-ex 1810 df-sb 2097 df-clab 2742 df-cleq 2755 df-ne 2959 df-rex 3090 df-dif 3908 df-nul 4287 |
| This theorem is used by: ssn0rex 4313 aks5lem7 42995 cycldlenngric 48721 |
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