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| Mirrors > Home > MPE Home > Th. List > n0rex | Structured version Visualization version GIF version | ||
| Description: There is an element in a nonempty class which is an element of the class. (Contributed by AV, 17-Dec-2020.) |
| Ref | Expression |
|---|---|
| n0rex | ⊢ (𝐴 ≠ ∅ → ∃𝑥 ∈ 𝐴 𝑥 ∈ 𝐴) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | id 23 | . . . 4 ⊢ (𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐴) | |
| 2 | 1 | ancli 558 | . . 3 ⊢ (𝑥 ∈ 𝐴 → (𝑥 ∈ 𝐴 ∧ 𝑥 ∈ 𝐴)) |
| 3 | 2 | eximi 1868 | . 2 ⊢ (∃𝑥 𝑥 ∈ 𝐴 → ∃𝑥(𝑥 ∈ 𝐴 ∧ 𝑥 ∈ 𝐴)) |
| 4 | n0 4300 | . 2 ⊢ (𝐴 ≠ ∅ ↔ ∃𝑥 𝑥 ∈ 𝐴) | |
| 5 | df-rex 3087 | . 2 ⊢ (∃𝑥 ∈ 𝐴 𝑥 ∈ 𝐴 ↔ ∃𝑥(𝑥 ∈ 𝐴 ∧ 𝑥 ∈ 𝐴)) | |
| 6 | 3, 4, 5 | 3imtr4i 295 | 1 ⊢ (𝐴 ≠ ∅ → ∃𝑥 ∈ 𝐴 𝑥 ∈ 𝐴) |
| Colors of variables: wff setvar class |
| This proof depends on syntax axioms: → wi 4 ∧ wa 401 ∃wex 1812 ∈ wcel 2145 ≠ wne 2955 ∃wrex 3086 ∅c0 4279 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1828 ax-4 1842 ax-5 1943 ax-6 2000 ax-7 2041 ax-9 2155 ax-ext 2732 |
| This proof depends on definitions: df-bi 210 df-an 402 df-tru 1573 df-fal 1583 df-ex 1813 df-sb 2100 df-clab 2739 df-cleq 2752 df-ne 2956 df-rex 3087 df-dif 3902 df-nul 4280 |
| This theorem is used by: ssn0rex 4306 aks5lem7 43131 cycldlenngric 48909 |
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