Theorem pm11.6 45143

Description: Theorem *11.6 in [WhiteheadRussell] p. 165. (Contributed by Andrew Salmon, 25-May-2011.)

Assertion

Ref	Expression
pm11.6	⊢ (∃𝑥(∃𝑦(𝜑 ∧ 𝜓) ∧ 𝜒) ↔ ∃𝑦(∃𝑥(𝜑 ∧ 𝜒) ∧ 𝜓))

Distinct variable groups:   𝜓,𝑥   𝜒,𝑦

Allowed substitution hints:   𝜑(𝑥, 𝑦)   𝜓(𝑦)   𝜒(𝑥)

Proof of Theorem pm11.6

Step	Hyp	Ref	Expression
1		excom 2200	. . 3 ⊢ (∃𝑥∃𝑦((𝜑 ∧ 𝜓) ∧ 𝜒) ↔ ∃𝑦∃𝑥((𝜑 ∧ 𝜓) ∧ 𝜒))
2		an32 659	. . . 4 ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) ↔ ((𝜑 ∧ 𝜒) ∧ 𝜓))
3	2	2exbii 1882	. . 3 ⊢ (∃𝑦∃𝑥((𝜑 ∧ 𝜓) ∧ 𝜒) ↔ ∃𝑦∃𝑥((𝜑 ∧ 𝜒) ∧ 𝜓))
4	1, 3	bitri 278	. 2 ⊢ (∃𝑥∃𝑦((𝜑 ∧ 𝜓) ∧ 𝜒) ↔ ∃𝑦∃𝑥((𝜑 ∧ 𝜒) ∧ 𝜓))
5		19.41v 1982	. . 3 ⊢ (∃𝑦((𝜑 ∧ 𝜓) ∧ 𝜒) ↔ (∃𝑦(𝜑 ∧ 𝜓) ∧ 𝜒))
6	5	exbii 1881	. 2 ⊢ (∃𝑥∃𝑦((𝜑 ∧ 𝜓) ∧ 𝜒) ↔ ∃𝑥(∃𝑦(𝜑 ∧ 𝜓) ∧ 𝜒))
7		19.41v 1982	. . 3 ⊢ (∃𝑥((𝜑 ∧ 𝜒) ∧ 𝜓) ↔ (∃𝑥(𝜑 ∧ 𝜒) ∧ 𝜓))
8	7	exbii 1881	. 2 ⊢ (∃𝑦∃𝑥((𝜑 ∧ 𝜒) ∧ 𝜓) ↔ ∃𝑦(∃𝑥(𝜑 ∧ 𝜒) ∧ 𝜓))
9	4, 6, 8	3bitr3i 304	1 ⊢ (∃𝑥(∃𝑦(𝜑 ∧ 𝜓) ∧ 𝜒) ↔ ∃𝑦(∃𝑥(𝜑 ∧ 𝜒) ∧ 𝜓))

This proof depends on syntax axioms:   ↔ wb 209   ∧ wa 401  ∃wex 1812

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-11 2195

This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1813

This theorem is used by: (None)