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Theorem sbceqal 3782
Description: Class version of one implication of equvelv 2034. (Contributed by Andrew Salmon, 28-Jun-2011.) (Proof shortened by SN, 26-Oct-2024.)
Assertion
Ref Expression
sbceqal (𝐴𝑉 → (∀𝑥(𝑥 = 𝐴𝑥 = 𝐵) → 𝐴 = 𝐵))
Distinct variable groups:   𝑥,𝐵   𝑥,𝐴
Allowed substitution hint:   𝑉(𝑥)

Proof of Theorem sbceqal
StepHypRef Expression
1 eqeq1 2742 . . . 4 (𝑥 = 𝐴 → (𝑥 = 𝐴𝐴 = 𝐴))
2 eqeq1 2742 . . . 4 (𝑥 = 𝐴 → (𝑥 = 𝐵𝐴 = 𝐵))
31, 2imbi12d 345 . . 3 (𝑥 = 𝐴 → ((𝑥 = 𝐴𝑥 = 𝐵) ↔ (𝐴 = 𝐴𝐴 = 𝐵)))
4 eqid 2738 . . . 4 𝐴 = 𝐴
54a1bi 363 . . 3 (𝐴 = 𝐵 ↔ (𝐴 = 𝐴𝐴 = 𝐵))
63, 5bitr4di 289 . 2 (𝑥 = 𝐴 → ((𝑥 = 𝐴𝑥 = 𝐵) ↔ 𝐴 = 𝐵))
76spcgv 3535 1 (𝐴𝑉 → (∀𝑥(𝑥 = 𝐴𝑥 = 𝐵) → 𝐴 = 𝐵))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wal 1537   = wceq 1539  wcel 2106
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1798  ax-4 1812  ax-5 1913  ax-6 1971  ax-7 2011  ax-8 2108  ax-9 2116  ax-ext 2709
This theorem depends on definitions:  df-bi 206  df-an 397  df-tru 1542  df-ex 1783  df-sb 2068  df-clab 2716  df-cleq 2730  df-clel 2816  df-v 3434
This theorem is referenced by:  sbeqalb  3784
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