Theorem spcgv 3550

Description: Rule of specialization, using implicit substitution. Compare Theorem 7.3 of [Quine] p. 44. (Contributed by NM, 22-Jun-1994.) Avoid ax-10 2178, ax-11 2194. (Revised by Wolf Lammen, 25-Aug-2023.)

Hypothesis

Ref	Expression
spcgv.1	⊢ (𝑥 = 𝐴 → (𝜑 ↔ 𝜓))

Assertion

Ref	Expression
spcgv	⊢ (𝐴 ∈ 𝑉 → (∀𝑥𝜑 → 𝜓))

Distinct variable groups:   𝜓,𝑥   𝑥,𝐴

Allowed substitution hints:   𝜑(𝑥)   𝑉(𝑥)

Proof of Theorem spcgv

Step	Hyp	Ref	Expression
1		elex 3471	. 2 ⊢ (𝐴 ∈ 𝑉 → 𝐴 ∈ V)
2		elex 3471	. . 3 ⊢ (𝐴 ∈ V → 𝐴 ∈ V)
3		spcgv.1	. . . 4 ⊢ (𝑥 = 𝐴 → (𝜑 ↔ 𝜓))
4	3	adantl 487	. . 3 ⊢ ((𝐴 ∈ V ∧ 𝑥 = 𝐴) → (𝜑 ↔ 𝜓))
5	2, 4	spcdv 3548	. 2 ⊢ (𝐴 ∈ V → (∀𝑥𝜑 → 𝜓))
6	1, 5	syl 18	1 ⊢ (𝐴 ∈ 𝑉 → (∀𝑥𝜑 → 𝜓))

This proof depends on syntax axioms:   → wi 4   ↔ wb 209  ∀wal 1568   = wceq 1570   ∈ wcel 2145  Vcvv 3450

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2732

This proof depends on definitions:  df-bi 210  df-an 402  df-tru 1573  df-ex 1813  df-sb 2100  df-clab 2739  df-cleq 2752  df-clel 2835  df-v 3452

This theorem is used by:  spcv  3559  mob2  3673  sbceqal  3800  intss1  4923  alxfr  5372  funmo  6551  isofrlem  7344  tfisi  7861  limomss  7873  nnlim  7882  f1oweALT  7975  pssnn  9170  findcard3  9260  frmin  9738  ttukeylem1  10536  rami  17132  ramcl  17146  islbs3  21372  mplsubglem  22245  mpllsslem  22246  uniopn  23154  chlimi  31747  iinabrex  33074  dfon2lem3  36445  dfon2lem8  36450  neificl  38568  hashnexinj  43059  ismrcd1  43608  mnuop23d  45155  relpfrlem  45841  modelaxreplem2  45867