| Mathbox for BTernaryTau |
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| Mirrors > Home > MPE Home > Th. List > Mathboxes > scott0i | Structured version Visualization version GIF version | ||
| Description: Applying Scott's trick to the empty set leaves it unchanged. (Contributed by BTernaryTau, 3-Jul-2026.) |
| Ref | Expression |
|---|---|
| scott0i | ⊢ Scott ∅ = ∅ |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | scottss 9869 | . 2 ⊢ Scott ∅ ⊆ ∅ | |
| 2 | ss0 4366 | . 2 ⊢ (Scott ∅ ⊆ ∅ → Scott ∅ = ∅) | |
| 3 | 1, 2 | ax-mp 5 | 1 ⊢ Scott ∅ = ∅ |
| Colors of variables: wff setvar class |
| Syntax hints: = wceq 1567 ⊆ wss 3913 ∅c0 4294 Scott cscott 9857 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1822 ax-4 1836 ax-5 1937 ax-6 1994 ax-7 2035 ax-8 2151 ax-9 2159 ax-ext 2741 |
| This theorem depends on definitions: df-bi 210 df-an 401 df-tru 1570 df-fal 1580 df-ex 1807 df-sb 2098 df-clab 2748 df-cleq 2761 df-clel 2844 df-rab 3424 df-dif 3916 df-ss 3930 df-nul 4295 df-scott 9858 |
| This theorem is referenced by: kardval 35498 |
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