Theorem symdifcom 4102

Description: Symmetric difference commutes. (Contributed by Scott Fenton, 24-Apr-2012.)

Assertion

Ref	Expression
symdifcom	⊢ (𝐴 △ 𝐵) = (𝐵 △ 𝐴)

Proof of Theorem symdifcom

Step	Hyp	Ref	Expression
1		uncom 4014	. 2 ⊢ ((𝐴 ∖ 𝐵) ∪ (𝐵 ∖ 𝐴)) = ((𝐵 ∖ 𝐴) ∪ (𝐴 ∖ 𝐵))
2		df-symdif 4101	. 2 ⊢ (𝐴 △ 𝐵) = ((𝐴 ∖ 𝐵) ∪ (𝐵 ∖ 𝐴))
3		df-symdif 4101	. 2 ⊢ (𝐵 △ 𝐴) = ((𝐵 ∖ 𝐴) ∪ (𝐴 ∖ 𝐵))
4	1, 2, 3	3eqtr4i 2806	1 ⊢ (𝐴 △ 𝐵) = (𝐵 △ 𝐴)

Syntax hints:   = wceq 1507   ∖ cdif 3822   ∪ cun 3823   △ csymdif 4100

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1758  ax-4 1772  ax-5 1869  ax-6 1928  ax-7 1964  ax-8 2050  ax-9 2057  ax-10 2077  ax-11 2091  ax-12 2104  ax-ext 2745

This theorem depends on definitions:  df-bi 199  df-an 388  df-or 834  df-tru 1510  df-ex 1743  df-nf 1747  df-sb 2014  df-clab 2754  df-cleq 2765  df-clel 2840  df-nfc 2912  df-v 3411  df-un 3830  df-symdif 4101

This theorem is referenced by:  symdifeq2  4104