Theorem wl-equsaldv 38252

Description: Deduction version of equsal 2451. (Contributed by Wolf Lammen, 27-Jul-2019.)

Hypotheses

Ref	Expression
wl-equsald.1	⊢ Ⅎ𝑥𝜑
wl-equsald.2	⊢ (𝜑 → Ⅎ𝑥𝜒)
wl-equsald.3	⊢ (𝜑 → (𝑥 = 𝑦 → (𝜓 ↔ 𝜒)))

Assertion

Ref	Expression
wl-equsaldv	⊢ (𝜑 → (∀𝑥(𝑥 = 𝑦 → 𝜓) ↔ 𝜒))

Distinct variable group:   𝑥,𝑦

Allowed substitution hints:   𝜑(𝑥, 𝑦)   𝜓(𝑥, 𝑦)   𝜒(𝑥, 𝑦)

Proof of Theorem wl-equsaldv

Step	Hyp	Ref	Expression
1		wl-equsald.2	. . 3 ⊢ (𝜑 → Ⅎ𝑥𝜒)
2		19.23t 2249	. . 3 ⊢ (Ⅎ𝑥𝜒 → (∀𝑥(𝑥 = 𝑦 → 𝜒) ↔ (∃𝑥 𝑥 = 𝑦 → 𝜒)))
3	1, 2	syl 18	. 2 ⊢ (𝜑 → (∀𝑥(𝑥 = 𝑦 → 𝜒) ↔ (∃𝑥 𝑥 = 𝑦 → 𝜒)))
4		wl-equsald.1	. . 3 ⊢ Ⅎ𝑥𝜑
5		wl-equsald.3	. . . 4 ⊢ (𝜑 → (𝑥 = 𝑦 → (𝜓 ↔ 𝜒)))
6	5	pm5.74d 276	. . 3 ⊢ (𝜑 → ((𝑥 = 𝑦 → 𝜓) ↔ (𝑥 = 𝑦 → 𝜒)))
7	4, 6	albid 2261	. 2 ⊢ (𝜑 → (∀𝑥(𝑥 = 𝑦 → 𝜓) ↔ ∀𝑥(𝑥 = 𝑦 → 𝜒)))
8		ax6ev 2002	. . . 4 ⊢ ∃𝑥 𝑥 = 𝑦
9	8	a1bi 365	. . 3 ⊢ (𝜒 ↔ (∃𝑥 𝑥 = 𝑦 → 𝜒))
10	9	a1i 11	. 2 ⊢ (𝜑 → (𝜒 ↔ (∃𝑥 𝑥 = 𝑦 → 𝜒)))
11	3, 7, 10	3bitr4d 314	1 ⊢ (𝜑 → (∀𝑥(𝑥 = 𝑦 → 𝜓) ↔ 𝜒))

This proof depends on syntax axioms:   → wi 4   ↔ wb 209  ∀wal 1568  ∃wex 1812  Ⅎwnf 1816

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-12 2216

This proof depends on definitions:  df-bi 210  df-ex 1813  df-nf 1817

This theorem is used by:  wl-sbid2ft  38257