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Theorem abss 3335
 Description: Class abstraction in a subclass relationship. (Contributed by NM, 16-Aug-2006.)
Assertion
Ref Expression
abss ({x φ} Ax(φx A))
Distinct variable group:   x,A
Allowed substitution hint:   φ(x)

Proof of Theorem abss
StepHypRef Expression
1 abid2 2470 . . 3 {x x A} = A
21sseq2i 3296 . 2 ({x φ} {x x A} ↔ {x φ} A)
3 ss2ab 3334 . 2 ({x φ} {x x A} ↔ x(φx A))
42, 3bitr3i 242 1 ({x φ} Ax(φx A))
 Colors of variables: wff setvar class Syntax hints:   → wi 4   ↔ wb 176  ∀wal 1540   ∈ wcel 1710  {cab 2339   ⊆ wss 3257 This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-6 1729  ax-7 1734  ax-11 1746  ax-12 1925  ax-ext 2334 This theorem depends on definitions:  df-bi 177  df-or 359  df-an 360  df-nan 1288  df-tru 1319  df-ex 1542  df-nf 1545  df-sb 1649  df-clab 2340  df-cleq 2346  df-clel 2349  df-nfc 2478  df-v 2861  df-nin 3211  df-compl 3212  df-in 3213  df-ss 3259 This theorem is referenced by:  abssdv  3340  rabss  3343  uniiunlem  3353  iunss  4007
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