Theorem poeq2 4285

Description: Equality theorem for partial ordering predicate. (Contributed by NM, 27-Mar-1997.)

Assertion

Ref	Expression
poeq2	|- ( A = B -> ( R Po A <-> R Po B ) )

Proof of Theorem poeq2

Step	Hyp	Ref	Expression
1		eqimss2 3202	. . 3 |- ( A = B -> B C_ A )
2		poss 4283	. . 3 |- ( B C_ A -> ( R Po A -> R Po B ) )
3	1, 2	syl 14	. 2 |- ( A = B -> ( R Po A -> R Po B ) )
4		eqimss 3201	. . 3 |- ( A = B -> A C_ B )
5		poss 4283	. . 3 |- ( A C_ B -> ( R Po B -> R Po A ) )
6	4, 5	syl 14	. 2 |- ( A = B -> ( R Po B -> R Po A ) )
7	3, 6	impbid 128	1 |- ( A = B -> ( R Po A <-> R Po B ) )

Syntax hints:   -> wi 4   <-> wb 104   = wceq 1348   C_ wss 3121   Po wpo 4279

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1440  ax-7 1441  ax-gen 1442  ax-ie1 1486  ax-ie2 1487  ax-8 1497  ax-11 1499  ax-4 1503  ax-17 1519  ax-i9 1523  ax-ial 1527  ax-i5r 1528  ax-ext 2152

This theorem depends on definitions:  df-bi 116  df-nf 1454  df-sb 1756  df-clab 2157  df-cleq 2163  df-clel 2166  df-ral 2453  df-in 3127  df-ss 3134  df-po 4281

This theorem is referenced by: (None)