Theorem poeq2 4278

Description: Equality theorem for partial ordering predicate. (Contributed by NM, 27-Mar-1997.)

Assertion

Ref	Expression
poeq2	|- ( A = B -> ( R Po A <-> R Po B ) )

Proof of Theorem poeq2

Step	Hyp	Ref	Expression
1		eqimss2 3197	. . 3 |- ( A = B -> B C_ A )
2		poss 4276	. . 3 |- ( B C_ A -> ( R Po A -> R Po B ) )
3	1, 2	syl 14	. 2 |- ( A = B -> ( R Po A -> R Po B ) )
4		eqimss 3196	. . 3 |- ( A = B -> A C_ B )
5		poss 4276	. . 3 |- ( A C_ B -> ( R Po B -> R Po A ) )
6	4, 5	syl 14	. 2 |- ( A = B -> ( R Po B -> R Po A ) )
7	3, 6	impbid 128	1 |- ( A = B -> ( R Po A <-> R Po B ) )

Syntax hints:   -> wi 4   <-> wb 104   = wceq 1343   C_ wss 3116   Po wpo 4272

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1435  ax-7 1436  ax-gen 1437  ax-ie1 1481  ax-ie2 1482  ax-8 1492  ax-11 1494  ax-4 1498  ax-17 1514  ax-i9 1518  ax-ial 1522  ax-i5r 1523  ax-ext 2147

This theorem depends on definitions:  df-bi 116  df-nf 1449  df-sb 1751  df-clab 2152  df-cleq 2158  df-clel 2161  df-ral 2449  df-in 3122  df-ss 3129  df-po 4274

This theorem is referenced by: (None)