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Theorem sbco2vd 2018
Description: Version of sbco2d 2017 with a distinct variable constraint between  x and  z. (Contributed by Jim Kingdon, 19-Feb-2018.)
Hypotheses
Ref Expression
sbco2vd.1  |-  ( ph  ->  A. x ph )
sbco2vd.2  |-  ( ph  ->  A. z ph )
sbco2vd.3  |-  ( ph  ->  ( ps  ->  A. z ps ) )
Assertion
Ref Expression
sbco2vd  |-  ( ph  ->  ( [ y  / 
z ] [ z  /  x ] ps  <->  [ y  /  x ] ps ) )
Distinct variable group:    x, z
Allowed substitution hints:    ph( x, y, z)    ps( x, y, z)

Proof of Theorem sbco2vd
StepHypRef Expression
1 sbco2vd.2 . . . . 5  |-  ( ph  ->  A. z ph )
2 sbco2vd.3 . . . . 5  |-  ( ph  ->  ( ps  ->  A. z ps ) )
31, 2hbim1 1616 . . . 4  |-  ( (
ph  ->  ps )  ->  A. z ( ph  ->  ps ) )
43sbco2vh 1996 . . 3  |-  ( [ y  /  z ] [ z  /  x ] ( ph  ->  ps )  <->  [ y  /  x ] ( ph  ->  ps ) )
5 sbco2vd.1 . . . . . 6  |-  ( ph  ->  A. x ph )
65sbrim 2007 . . . . 5  |-  ( [ z  /  x ]
( ph  ->  ps )  <->  (
ph  ->  [ z  /  x ] ps ) )
76sbbii 1811 . . . 4  |-  ( [ y  /  z ] [ z  /  x ] ( ph  ->  ps )  <->  [ y  /  z ] ( ph  ->  [ z  /  x ] ps ) )
81sbrim 2007 . . . 4  |-  ( [ y  /  z ] ( ph  ->  [ z  /  x ] ps ) 
<->  ( ph  ->  [ y  /  z ] [
z  /  x ] ps ) )
97, 8bitri 184 . . 3  |-  ( [ y  /  z ] [ z  /  x ] ( ph  ->  ps )  <->  ( ph  ->  [ y  /  z ] [ z  /  x ] ps ) )
105sbrim 2007 . . 3  |-  ( [ y  /  x ]
( ph  ->  ps )  <->  (
ph  ->  [ y  /  x ] ps ) )
114, 9, 103bitr3i 210 . 2  |-  ( (
ph  ->  [ y  / 
z ] [ z  /  x ] ps ) 
<->  ( ph  ->  [ y  /  x ] ps ) )
1211pm5.74ri 181 1  |-  ( ph  ->  ( [ y  / 
z ] [ z  /  x ] ps  <->  [ y  /  x ] ps ) )
Colors of variables: wff set class
Syntax hints:    -> wi 4    <-> wb 105   A.wal 1393   [wsb 1808
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 714  ax-5 1493  ax-7 1494  ax-gen 1495  ax-ie1 1539  ax-ie2 1540  ax-8 1550  ax-10 1551  ax-11 1552  ax-i12 1553  ax-4 1556  ax-17 1572  ax-i9 1576  ax-ial 1580  ax-i5r 1581
This theorem depends on definitions:  df-bi 117  df-nf 1507  df-sb 1809
This theorem is referenced by: (None)
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