Theorem undif1ss 3586

Description: Absorption of difference by union. In classical logic, as Theorem 35 of [Suppes] p. 29, this would be equality rather than subset. (Contributed by Jim Kingdon, 4-Aug-2018.)

Assertion

Ref	Expression
undif1ss	|- ( ( A \ B ) u. B ) C_ ( A u. B )

Proof of Theorem undif1ss

Step	Hyp	Ref	Expression
1		difss 3347	. 2 |- ( A \ B ) C_ A
2		unss1 3390	. 2 |- ( ( A \ B ) C_ A -> ( ( A \ B ) u. B ) C_ ( A u. B ) )
3	1, 2	ax-mp 5	1 |- ( ( A \ B ) u. B ) C_ ( A u. B )

Syntax hints:   \ cdif 3210   u. cun 3211   C_ wss 3213

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 619  ax-in2 620  ax-io 717  ax-5 1496  ax-7 1497  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-8 1553  ax-10 1554  ax-11 1555  ax-i12 1556  ax-bndl 1558  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583  ax-i5r 1584  ax-ext 2216

This theorem depends on definitions:  df-bi 117  df-tru 1401  df-nf 1510  df-sb 1812  df-clab 2221  df-cleq 2227  df-clel 2230  df-nfc 2375  df-v 2817  df-dif 3215  df-un 3217  df-in 3219  df-ss 3226

This theorem is referenced by:  undif2ss  3587  pwundifss  4408