Theorem embantd 56

Description: Deduction embedding an antecedent. (Contributed by Wolf Lammen, 4-Oct-2013.)

Hypotheses

Ref	Expression
embantd.1	⊢ (𝜑 → 𝜓)
embantd.2	⊢ (𝜑 → (𝜒 → 𝜃))

Assertion

Ref	Expression
embantd	⊢ (𝜑 → ((𝜓 → 𝜒) → 𝜃))

Proof of Theorem embantd

Step	Hyp	Ref	Expression
1		embantd.1	. 2 ⊢ (𝜑 → 𝜓)
2		embantd.2	. . 3 ⊢ (𝜑 → (𝜒 → 𝜃))
3	2	imim2d 54	. 2 ⊢ (𝜑 → ((𝜓 → 𝜒) → (𝜓 → 𝜃)))
4	1, 3	mpid 42	1 ⊢ (𝜑 → ((𝜓 → 𝜒) → 𝜃))

Syntax hints:   → wi 4

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7

This theorem is referenced by:  a2and  528  el  4042  findcard2d  6714  findcard2sd  6715  exprmfct  11611  sqrt2irr  11633  iscnp4  12168  bj-exlimmp  12558