Theorem abeqabi 42092

Description: Generalized condition for a class abstraction to be equal to some class. (Contributed by RP, 2-Sep-2024.)

Hypothesis

Ref	Expression
abeqabi.a	⊢ 𝐴 = {𝑥 ∣ 𝜓}

Assertion

Ref	Expression
abeqabi	⊢ ({𝑥 ∣ 𝜑} = 𝐴 ↔ ∀𝑥(𝜑 ↔ 𝜓))

Proof of Theorem abeqabi

Step	Hyp	Ref	Expression
1		abeqabi.a	. . 3 ⊢ 𝐴 = {𝑥 ∣ 𝜓}
2	1	eqeq2i 2746	. 2 ⊢ ({𝑥 ∣ 𝜑} = 𝐴 ↔ {𝑥 ∣ 𝜑} = {𝑥 ∣ 𝜓})
3		abbib 2805	. 2 ⊢ ({𝑥 ∣ 𝜑} = {𝑥 ∣ 𝜓} ↔ ∀𝑥(𝜑 ↔ 𝜓))
4	2, 3	bitri 275	1 ⊢ ({𝑥 ∣ 𝜑} = 𝐴 ↔ ∀𝑥(𝜑 ↔ 𝜓))

Syntax hints:   ↔ wb 205  ∀wal 1540   = wceq 1542  {cab 2710

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1798  ax-4 1812  ax-5 1914  ax-6 1972  ax-7 2012  ax-9 2117  ax-10 2138  ax-11 2155  ax-12 2172  ax-ext 2704

This theorem depends on definitions:  df-bi 206  df-an 398  df-or 847  df-tru 1545  df-ex 1783  df-nf 1787  df-sb 2069  df-clab 2711  df-cleq 2725

This theorem is referenced by:  abpr  42093  abtp  42094