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| Mirrors > Home > MPE Home > Th. List > Mathboxes > abtp | Structured version Visualization version GIF version | ||
| Description: Condition for a class abstraction to be a triple. (Contributed by RP, 25-Aug-2024.) |
| Ref | Expression |
|---|---|
| abtp | ⊢ ({𝑥 ∣ 𝜑} = {𝑋, 𝑌, 𝑍} ↔ ∀𝑥(𝜑 ↔ (𝑥 = 𝑋 ∨ 𝑥 = 𝑌 ∨ 𝑥 = 𝑍))) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | dftp2 4650 | . 2 ⊢ {𝑋, 𝑌, 𝑍} = {𝑥 ∣ (𝑥 = 𝑋 ∨ 𝑥 = 𝑌 ∨ 𝑥 = 𝑍)} | |
| 2 | 1 | abeqabi 43984 | 1 ⊢ ({𝑥 ∣ 𝜑} = {𝑋, 𝑌, 𝑍} ↔ ∀𝑥(𝜑 ↔ (𝑥 = 𝑋 ∨ 𝑥 = 𝑌 ∨ 𝑥 = 𝑍))) |
| Colors of variables: wff setvar class |
| Syntax hints: ↔ wb 208 ∨ w3o 1097 ∀wal 1558 = wceq 1560 {cab 2740 {ctp 4586 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1815 ax-4 1829 ax-5 1930 ax-6 1987 ax-7 2028 ax-8 2144 ax-9 2152 ax-10 2175 ax-11 2191 ax-12 2212 ax-ext 2734 |
| This theorem depends on definitions: df-bi 209 df-an 400 df-or 859 df-3or 1099 df-tru 1563 df-ex 1800 df-nf 1804 df-sb 2091 df-clab 2741 df-cleq 2754 df-clel 2837 df-v 3456 df-un 3909 df-sn 4583 df-pr 4585 df-tp 4587 |
| This theorem is referenced by: (None) |
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