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| Mirrors > Home > MPE Home > Th. List > Mathboxes > abtp | Structured version Visualization version GIF version | ||
| Description: Condition for a class abstraction to be a triple. (Contributed by RP, 25-Aug-2024.) |
| Ref | Expression |
|---|---|
| abtp | ⊢ ({𝑥 ∣ 𝜑} = {𝑋, 𝑌, 𝑍} ↔ ∀𝑥(𝜑 ↔ (𝑥 = 𝑋 ∨ 𝑥 = 𝑌 ∨ 𝑥 = 𝑍))) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | dftp2 4626 | . 2 ⊢ {𝑋, 𝑌, 𝑍} = {𝑥 ∣ (𝑥 = 𝑋 ∨ 𝑥 = 𝑌 ∨ 𝑥 = 𝑍)} | |
| 2 | 1 | abeqabi 43867 | 1 ⊢ ({𝑥 ∣ 𝜑} = {𝑋, 𝑌, 𝑍} ↔ ∀𝑥(𝜑 ↔ (𝑥 = 𝑋 ∨ 𝑥 = 𝑌 ∨ 𝑥 = 𝑍))) |
| Colors of variables: wff setvar class |
| Syntax hints: ↔ wb 208 ∨ w3o 1092 ∀wal 1546 = wceq 1548 {cab 2719 {ctp 4562 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1803 ax-4 1817 ax-5 1918 ax-6 1975 ax-7 2016 ax-8 2123 ax-9 2131 ax-10 2154 ax-11 2170 ax-12 2191 ax-ext 2713 |
| This theorem depends on definitions: df-bi 209 df-an 398 df-or 855 df-3or 1094 df-tru 1551 df-ex 1788 df-nf 1792 df-sb 2075 df-clab 2720 df-cleq 2733 df-clel 2816 df-v 3435 df-un 3890 df-sn 4559 df-pr 4561 df-tp 4563 |
| This theorem is referenced by: (None) |
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