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| Mirrors > Home > MPE Home > Th. List > Mathboxes > abtp | Structured version Visualization version GIF version | ||
| Description: Condition for a class abstraction to be a triple. (Contributed by RP, 25-Aug-2024.) |
| Ref | Expression |
|---|---|
| abtp | ⊢ ({𝑥 ∣ 𝜑} = {𝑋, 𝑌, 𝑍} ↔ ∀𝑥(𝜑 ↔ (𝑥 = 𝑋 ∨ 𝑥 = 𝑌 ∨ 𝑥 = 𝑍))) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | dftp2 4662 | . 2 ⊢ {𝑋, 𝑌, 𝑍} = {𝑥 ∣ (𝑥 = 𝑋 ∨ 𝑥 = 𝑌 ∨ 𝑥 = 𝑍)} | |
| 2 | 1 | abeqabi 44025 | 1 ⊢ ({𝑥 ∣ 𝜑} = {𝑋, 𝑌, 𝑍} ↔ ∀𝑥(𝜑 ↔ (𝑥 = 𝑋 ∨ 𝑥 = 𝑌 ∨ 𝑥 = 𝑍))) |
| Colors of variables: wff setvar class |
| Syntax hints: ↔ wb 209 ∨ w3o 1100 ∀wal 1565 = wceq 1567 {cab 2747 {ctp 4598 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1822 ax-4 1836 ax-5 1937 ax-6 1994 ax-7 2035 ax-8 2151 ax-9 2159 ax-10 2182 ax-11 2198 ax-12 2219 ax-ext 2741 |
| This theorem depends on definitions: df-bi 210 df-an 401 df-or 861 df-3or 1102 df-tru 1570 df-ex 1807 df-nf 1811 df-sb 2098 df-clab 2748 df-cleq 2761 df-clel 2844 df-v 3465 df-un 3918 df-sn 4595 df-pr 4597 df-tp 4599 |
| This theorem is referenced by: (None) |
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