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Theorem ax6vsep 5257
Description: Derive ax6v 2001 (a weakened version of ax-6 2000 where 𝑥 and 𝑦 must be distinct), from Separation ax-sep 5249 and Extensionality ax-ext 2733. See ax6 2414 for the derivation of ax-6 2000 from ax6v 2001. (Contributed by NM, 12-Nov-2013.) (Proof modification is discouraged.) (New usage is discouraged.)
Assertion
Ref Expression
ax6vsep ¬ ∀𝑥 ¬ 𝑥 = 𝑦
Distinct variable group:   𝑥,𝑦

Proof of Theorem ax6vsep
Dummy variable 𝑧 is distinct from all other variables.
StepHypRef Expression
1 ax-sep 5249 . . 3 ∃𝑥∀𝑧(𝑧 ∈ 𝑥 ↔ (𝑧 ∈ 𝑦 ∧ (𝑧 = 𝑧 → 𝑧 = 𝑧)))
2 id 23 . . . . . . . . 9 (𝑧 = 𝑧 → 𝑧 = 𝑧)
32biantru 539 . . . . . . . 8 (𝑧 ∈ 𝑦 ↔ (𝑧 ∈ 𝑦 ∧ (𝑧 = 𝑧 → 𝑧 = 𝑧)))
43bibi2i 340 . . . . . . 7 ((𝑧 ∈ 𝑥 ↔ 𝑧 ∈ 𝑦) ↔ (𝑧 ∈ 𝑥 ↔ (𝑧 ∈ 𝑦 ∧ (𝑧 = 𝑧 → 𝑧 = 𝑧))))
54biimpri 231 . . . . . 6 ((𝑧 ∈ 𝑥 ↔ (𝑧 ∈ 𝑦 ∧ (𝑧 = 𝑧 → 𝑧 = 𝑧))) → (𝑧 ∈ 𝑥 ↔ 𝑧 ∈ 𝑦))
65alimi 1844 . . . . 5 (∀𝑧(𝑧 ∈ 𝑥 ↔ (𝑧 ∈ 𝑦 ∧ (𝑧 = 𝑧 → 𝑧 = 𝑧))) → ∀𝑧(𝑧 ∈ 𝑥 ↔ 𝑧 ∈ 𝑦))
7 ax-ext 2733 . . . . 5 (∀𝑧(𝑧 ∈ 𝑥 ↔ 𝑧 ∈ 𝑦) → 𝑥 = 𝑦)
86, 7syl 18 . . . 4 (∀𝑧(𝑧 ∈ 𝑥 ↔ (𝑧 ∈ 𝑦 ∧ (𝑧 = 𝑧 → 𝑧 = 𝑧))) → 𝑥 = 𝑦)
98eximi 1868 . . 3 (∃𝑥∀𝑧(𝑧 ∈ 𝑥 ↔ (𝑧 ∈ 𝑦 ∧ (𝑧 = 𝑧 → 𝑧 = 𝑧))) → ∃𝑥 𝑥 = 𝑦)
101, 9ax-mp 5 . 2 ∃𝑥 𝑥 = 𝑦
11 df-ex 1813 . 2 (∃𝑥 𝑥 = 𝑦 ↔ ¬ ∀𝑥 ¬ 𝑥 = 𝑦)
1210, 11mpbi 233 1 ¬ ∀𝑥 ¬ 𝑥 = 𝑦
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  ¬ wn 3   → wi 4   ↔ wb 209   ∧ wa 401  ∀wal 1568   = wceq 1570  ∃wex 1812   ∈ wcel 2145
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-ext 2733  ax-sep 5249
This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1813
This theorem is used by: (None)
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