Theorem bj-cbv3ta 37449

Description: Closed form of cbv3 2428. (Contributed by BJ, 2-May-2019.)

Assertion

Ref	Expression
bj-cbv3ta	⊢ (∀𝑥∀𝑦(𝑥 = 𝑦 → (𝜑 → 𝜓)) → ((∀𝑦(∃𝑥𝜓 → 𝜓) ∧ ∀𝑥(𝜑 → ∀𝑦𝜑)) → (∀𝑥𝜑 → ∀𝑦𝜓)))

Proof of Theorem bj-cbv3ta

Step	Hyp	Ref	Expression
1		bj-spimt2 37448	. . . . . 6 ⊢ (∀𝑥(𝑥 = 𝑦 → (𝜑 → 𝜓)) → ((∃𝑥𝜓 → 𝜓) → (∀𝑥𝜑 → 𝜓)))
2	1	imp 411	. . . . 5 ⊢ ((∀𝑥(𝑥 = 𝑦 → (𝜑 → 𝜓)) ∧ (∃𝑥𝜓 → 𝜓)) → (∀𝑥𝜑 → 𝜓))
3	2	alanimi 1845	. . . 4 ⊢ ((∀𝑦∀𝑥(𝑥 = 𝑦 → (𝜑 → 𝜓)) ∧ ∀𝑦(∃𝑥𝜓 → 𝜓)) → ∀𝑦(∀𝑥𝜑 → 𝜓))
4		bj-hbalt 37333	. . . 4 ⊢ (∀𝑥(𝜑 → ∀𝑦𝜑) → (∀𝑥𝜑 → ∀𝑦∀𝑥𝜑))
5		sylgt 1851	. . . 4 ⊢ (∀𝑦(∀𝑥𝜑 → 𝜓) → ((∀𝑥𝜑 → ∀𝑦∀𝑥𝜑) → (∀𝑥𝜑 → ∀𝑦𝜓)))
6	3, 4, 5	syl2im 41	. . 3 ⊢ ((∀𝑦∀𝑥(𝑥 = 𝑦 → (𝜑 → 𝜓)) ∧ ∀𝑦(∃𝑥𝜓 → 𝜓)) → (∀𝑥(𝜑 → ∀𝑦𝜑) → (∀𝑥𝜑 → ∀𝑦𝜓)))
7	6	expimpd 458	. 2 ⊢ (∀𝑦∀𝑥(𝑥 = 𝑦 → (𝜑 → 𝜓)) → ((∀𝑦(∃𝑥𝜓 → 𝜓) ∧ ∀𝑥(𝜑 → ∀𝑦𝜑)) → (∀𝑥𝜑 → ∀𝑦𝜓)))
8	7	alcoms 2192	1 ⊢ (∀𝑥∀𝑦(𝑥 = 𝑦 → (𝜑 → 𝜓)) → ((∀𝑦(∃𝑥𝜓 → 𝜓) ∧ ∀𝑥(𝜑 → ∀𝑦𝜑)) → (∀𝑥𝜑 → ∀𝑦𝜓)))

This proof depends on syntax axioms:   → wi 4   ∧ wa 400  ∀wal 1567  ∃wex 1808

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1824  ax-4 1838  ax-5 1939  ax-6 1996  ax-7 2037  ax-11 2191  ax-12 2212  ax-13 2403

This proof depends on definitions:  df-bi 210  df-an 401  df-ex 1809

This theorem is used by:  bj-cbv3tb  37450