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| Mirrors > Home > MPE Home > Th. List > Mathboxes > bj-cbvaldvav | Structured version Visualization version GIF version | ||
| Description: Version of cbvaldva 2412 with a disjoint variable condition, which does not require ax-13 2375. (Contributed by BJ, 16-Jun-2019.) (Proof modification is discouraged.) |
| Ref | Expression |
|---|---|
| bj-cbvaldvav.1 | ⊢ ((𝜑 ∧ 𝑥 = 𝑦) → (𝜓 ↔ 𝜒)) |
| Ref | Expression |
|---|---|
| bj-cbvaldvav | ⊢ (𝜑 → (∀𝑥𝜓 ↔ ∀𝑦𝜒)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | nfv 1913 | . 2 ⊢ Ⅎ𝑦𝜑 | |
| 2 | nfvd 1914 | . 2 ⊢ (𝜑 → Ⅎ𝑦𝜓) | |
| 3 | bj-cbvaldvav.1 | . . 3 ⊢ ((𝜑 ∧ 𝑥 = 𝑦) → (𝜓 ↔ 𝜒)) | |
| 4 | 3 | ex 412 | . 2 ⊢ (𝜑 → (𝑥 = 𝑦 → (𝜓 ↔ 𝜒))) |
| 5 | 1, 2, 4 | bj-cbvaldv 36734 | 1 ⊢ (𝜑 → (∀𝑥𝜓 ↔ ∀𝑦𝜒)) |
| Colors of variables: wff setvar class |
| Syntax hints: → wi 4 ↔ wb 206 ∧ wa 395 ∀wal 1537 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1794 ax-4 1808 ax-5 1909 ax-6 1966 ax-7 2006 ax-10 2140 ax-11 2156 ax-12 2176 |
| This theorem depends on definitions: df-bi 207 df-an 396 df-or 848 df-ex 1779 df-nf 1783 |
| This theorem is referenced by: (None) |
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