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| Mirrors > Home > MPE Home > Th. List > Mathboxes > bj-cbvaldvav | Structured version Visualization version GIF version | ||
| Description: Version of cbvaldva 2439 with a disjoint variable condition, which does not require ax-13 2402. (Contributed by BJ, 16-Jun-2019.) (Proof modification is discouraged.) |
| Ref | Expression |
|---|---|
| bj-cbvaldvav.1 | ⊢ ((𝜑 ∧ 𝑥 = 𝑦) → (𝜓 ↔ 𝜒)) |
| Ref | Expression |
|---|---|
| bj-cbvaldvav | ⊢ (𝜑 → (∀𝑥𝜓 ↔ ∀𝑦𝜒)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | nfv 1933 | . 2 ⊢ Ⅎ𝑦𝜑 | |
| 2 | nfvd 1934 | . 2 ⊢ (𝜑 → Ⅎ𝑦𝜓) | |
| 3 | bj-cbvaldvav.1 | . . 3 ⊢ ((𝜑 ∧ 𝑥 = 𝑦) → (𝜓 ↔ 𝜒)) | |
| 4 | 3 | ex 416 | . 2 ⊢ (𝜑 → (𝑥 = 𝑦 → (𝜓 ↔ 𝜒))) |
| 5 | 1, 2, 4 | bj-cbvaldv 37237 | 1 ⊢ (𝜑 → (∀𝑥𝜓 ↔ ∀𝑦𝜒)) |
| Colors of variables: wff setvar class |
| Syntax hints: → wi 4 ↔ wb 208 ∧ wa 399 ∀wal 1557 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1814 ax-4 1828 ax-5 1929 ax-6 1986 ax-7 2027 ax-10 2174 ax-11 2190 ax-12 2211 |
| This theorem depends on definitions: df-bi 209 df-an 400 df-or 859 df-ex 1799 df-nf 1803 |
| This theorem is referenced by: (None) |
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