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Theorem bj-rexvw 37884
Description: A weak version of rexv 3477 not using ax-ext 2732 (nor df-cleq 2752, df-clel 2835, df-v 3452), and only core FOL axioms. See also bj-ralvw 37883. (Contributed by BJ, 16-Jun-2019.) (Proof modification is discouraged.)
Hypothesis
Ref Expression
bj-rexvw.1 𝜓
Assertion
Ref Expression
bj-rexvw (∃𝑥 ∈ {𝑦 ∣ 𝜓}𝜑 ↔ ∃𝑥𝜑)

Proof of Theorem bj-rexvw
StepHypRef Expression
1 df-rex 3087 . 2 (∃𝑥 ∈ {𝑦 ∣ 𝜓}𝜑 ↔ ∃𝑥(𝑥 ∈ {𝑦 ∣ 𝜓} ∧ 𝜑))
2 bj-rexvw.1 . . . . 5 𝜓
32vexw 2744 . . . 4 𝑥 ∈ {𝑦 ∣ 𝜓}
43biantrur 540 . . 3 (𝜑 ↔ (𝑥 ∈ {𝑦 ∣ 𝜓} ∧ 𝜑))
54exbii 1880 . 2 (∃𝑥𝜑 ↔ ∃𝑥(𝑥 ∈ {𝑦 ∣ 𝜓} ∧ 𝜑))
61, 5bitr4i 281 1 (∃𝑥 ∈ {𝑦 ∣ 𝜓}𝜑 ↔ ∃𝑥𝜑)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   ↔ wb 209   ∧ wa 401  ∃wex 1811   ∈ wcel 2144  {cab 2738  ∃wrex 3086
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841
This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1812  df-sb 2099  df-clab 2739  df-rex 3087
This theorem is used by: (None)
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