Theorem clel3g 3629

Description: Alternate definition of membership in a set. (Contributed by NM, 13-Aug-2005.)

Assertion

Ref	Expression
clel3g	⊢ (𝐵 ∈ 𝑉 → (𝐴 ∈ 𝐵 ↔ ∃𝑥(𝑥 = 𝐵 ∧ 𝐴 ∈ 𝑥)))

Distinct variable groups:   𝑥,𝐴   𝑥,𝐵

Allowed substitution hint:   𝑉(𝑥)

Proof of Theorem clel3g

Step	Hyp	Ref	Expression
1		eleq2 2858	. . 3 ⊢ (𝑥 = 𝐵 → (𝐴 ∈ 𝑥 ↔ 𝐴 ∈ 𝐵))
2	1	ceqsexgv 3622	. 2 ⊢ (𝐵 ∈ 𝑉 → (∃𝑥(𝑥 = 𝐵 ∧ 𝐴 ∈ 𝑥) ↔ 𝐴 ∈ 𝐵))
3	2	bicomd 226	1 ⊢ (𝐵 ∈ 𝑉 → (𝐴 ∈ 𝐵 ↔ ∃𝑥(𝑥 = 𝐵 ∧ 𝐴 ∈ 𝑥)))

Syntax hints:   → wi 4   ↔ wb 209   ∧ wa 400   = wceq 1567  ∃wex 1806   ∈ wcel 2149

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1822  ax-4 1836  ax-5 1937  ax-6 1994  ax-7 2035  ax-8 2151  ax-9 2159  ax-ext 2741

This theorem depends on definitions:  df-bi 210  df-an 401  df-tru 1570  df-ex 1807  df-sb 2098  df-clab 2748  df-cleq 2761  df-clel 2844

This theorem is referenced by:  clel3  3630  uniprg  4892