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Theorem ectocl 8788
Description: Implicit substitution of class for equivalence class. (Contributed by NM, 23-Jul-1995.) (Revised by Mario Carneiro, 9-Jul-2014.)
Hypotheses
Ref Expression
ectocl.1 𝑆 = (𝐵 / 𝑅)
ectocl.2 ([𝑥]𝑅 = 𝐴 → (𝜑 ↔ 𝜓))
ectocl.3 (𝑥 ∈ 𝐵 → 𝜑)
Assertion
Ref Expression
ectocl (𝐴 ∈ 𝑆 → 𝜓)
Distinct variable groups:   𝑥,𝐴   𝑥,𝐵   𝑥,𝑅   𝜓,𝑥
Allowed substitution hints:   𝜑(𝑥)   𝑆(𝑥)

Proof of Theorem ectocl
StepHypRef Expression
1 tru 1574 . 2 ⊤
2 ectocl.1 . . 3 𝑆 = (𝐵 / 𝑅)
3 ectocl.2 . . 3 ([𝑥]𝑅 = 𝐴 → (𝜑 ↔ 𝜓))
4 ectocl.3 . . . 4 (𝑥 ∈ 𝐵 → 𝜑)
54adantl 487 . . 3 ((⊤ ∧ 𝑥 ∈ 𝐵) → 𝜑)
62, 3, 5ectocld 8787 . 2 ((⊤ ∧ 𝐴 ∈ 𝑆) → 𝜓)
71, 6mpan 703 1 (𝐴 ∈ 𝑆 → 𝜓)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 209   = wceq 1570  ⊤wtru 1571   ∈ wcel 2145  [cec 8699   / cqs 8700
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2733
This proof depends on definitions:  df-bi 210  df-an 402  df-tru 1573  df-ex 1813  df-sb 2100  df-clab 2740  df-cleq 2753  df-clel 2836  df-rex 3088  df-qs 8707
This theorem is used by:  vitalilem2  25910
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