Theorem equncom 4100

Description: If a class equals the union of two other classes, then it equals the union of those two classes commuted. equncom 4100 was automatically derived from equncomVD 45315 using the tools program translate_without_overwriting.cmd and minimizing. (Contributed by Alan Sare, 18-Feb-2012.)

Assertion

Ref	Expression
equncom	⊢ (𝐴 = (𝐵 ∪ 𝐶) ↔ 𝐴 = (𝐶 ∪ 𝐵))

Proof of Theorem equncom

Step	Hyp	Ref	Expression
1		uncom 4099	. 2 ⊢ (𝐵 ∪ 𝐶) = (𝐶 ∪ 𝐵)
2	1	eqeq2i 2750	1 ⊢ (𝐴 = (𝐵 ∪ 𝐶) ↔ 𝐴 = (𝐶 ∪ 𝐵))

Syntax hints:   ↔ wb 206   = wceq 1542   ∪ cun 3888

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1912  ax-6 1969  ax-7 2010  ax-8 2116  ax-9 2124  ax-ext 2709

This theorem depends on definitions:  df-bi 207  df-an 396  df-or 849  df-tru 1545  df-ex 1782  df-sb 2069  df-clab 2716  df-cleq 2729  df-clel 2812  df-v 3432  df-un 3895

This theorem is referenced by:  equncomi  4101  equncomiVD  45316