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Type | Label | Description |
---|---|---|
Statement | ||
Theorem | sspsstri 4101 | Two ways of stating trichotomy with respect to inclusion. (Contributed by NM, 12-Aug-2004.) |
⊢ ((𝐴 ⊆ 𝐵 ∨ 𝐵 ⊆ 𝐴) ↔ (𝐴 ⊊ 𝐵 ∨ 𝐴 = 𝐵 ∨ 𝐵 ⊊ 𝐴)) | ||
Theorem | ssnpss 4102 | Partial trichotomy law for subclasses. (Contributed by NM, 16-May-1996.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ (𝐴 ⊆ 𝐵 → ¬ 𝐵 ⊊ 𝐴) | ||
Theorem | psstr 4103 | Transitive law for proper subclass. Theorem 9 of [Suppes] p. 23. (Contributed by NM, 7-Feb-1996.) |
⊢ ((𝐴 ⊊ 𝐵 ∧ 𝐵 ⊊ 𝐶) → 𝐴 ⊊ 𝐶) | ||
Theorem | sspsstr 4104 | Transitive law for subclass and proper subclass. (Contributed by NM, 3-Apr-1996.) |
⊢ ((𝐴 ⊆ 𝐵 ∧ 𝐵 ⊊ 𝐶) → 𝐴 ⊊ 𝐶) | ||
Theorem | psssstr 4105 | Transitive law for subclass and proper subclass. (Contributed by NM, 3-Apr-1996.) |
⊢ ((𝐴 ⊊ 𝐵 ∧ 𝐵 ⊆ 𝐶) → 𝐴 ⊊ 𝐶) | ||
Theorem | psstrd 4106 | Proper subclass inclusion is transitive. Deduction form of psstr 4103. (Contributed by David Moews, 1-May-2017.) |
⊢ (𝜑 → 𝐴 ⊊ 𝐵) & ⊢ (𝜑 → 𝐵 ⊊ 𝐶) ⇒ ⊢ (𝜑 → 𝐴 ⊊ 𝐶) | ||
Theorem | sspsstrd 4107 | Transitivity involving subclass and proper subclass inclusion. Deduction form of sspsstr 4104. (Contributed by David Moews, 1-May-2017.) |
⊢ (𝜑 → 𝐴 ⊆ 𝐵) & ⊢ (𝜑 → 𝐵 ⊊ 𝐶) ⇒ ⊢ (𝜑 → 𝐴 ⊊ 𝐶) | ||
Theorem | psssstrd 4108 | Transitivity involving subclass and proper subclass inclusion. Deduction form of psssstr 4105. (Contributed by David Moews, 1-May-2017.) |
⊢ (𝜑 → 𝐴 ⊊ 𝐵) & ⊢ (𝜑 → 𝐵 ⊆ 𝐶) ⇒ ⊢ (𝜑 → 𝐴 ⊊ 𝐶) | ||
Theorem | npss 4109 | A class is not a proper subclass of another iff it satisfies a one-directional form of eqss 3996. (Contributed by Mario Carneiro, 15-May-2015.) |
⊢ (¬ 𝐴 ⊊ 𝐵 ↔ (𝐴 ⊆ 𝐵 → 𝐴 = 𝐵)) | ||
Theorem | ssnelpss 4110 | A subclass missing a member is a proper subclass. (Contributed by NM, 12-Jan-2002.) |
⊢ (𝐴 ⊆ 𝐵 → ((𝐶 ∈ 𝐵 ∧ ¬ 𝐶 ∈ 𝐴) → 𝐴 ⊊ 𝐵)) | ||
Theorem | ssnelpssd 4111 | Subclass inclusion with one element of the superclass missing is proper subclass inclusion. Deduction form of ssnelpss 4110. (Contributed by David Moews, 1-May-2017.) |
⊢ (𝜑 → 𝐴 ⊆ 𝐵) & ⊢ (𝜑 → 𝐶 ∈ 𝐵) & ⊢ (𝜑 → ¬ 𝐶 ∈ 𝐴) ⇒ ⊢ (𝜑 → 𝐴 ⊊ 𝐵) | ||
Theorem | ssexnelpss 4112* | If there is an element of a class which is not contained in a subclass, the subclass is a proper subclass. (Contributed by AV, 29-Jan-2020.) |
⊢ ((𝐴 ⊆ 𝐵 ∧ ∃𝑥 ∈ 𝐵 𝑥 ∉ 𝐴) → 𝐴 ⊊ 𝐵) | ||
Theorem | dfdif3 4113* | Alternate definition of class difference. (Contributed by BJ and Jim Kingdon, 16-Jun-2022.) |
⊢ (𝐴 ∖ 𝐵) = {𝑥 ∈ 𝐴 ∣ ∀𝑦 ∈ 𝐵 𝑥 ≠ 𝑦} | ||
Theorem | difeq1 4114 | Equality theorem for class difference. (Contributed by NM, 10-Feb-1997.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ (𝐴 = 𝐵 → (𝐴 ∖ 𝐶) = (𝐵 ∖ 𝐶)) | ||
Theorem | difeq2 4115 | Equality theorem for class difference. (Contributed by NM, 10-Feb-1997.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ (𝐴 = 𝐵 → (𝐶 ∖ 𝐴) = (𝐶 ∖ 𝐵)) | ||
Theorem | difeq12 4116 | Equality theorem for class difference. (Contributed by FL, 31-Aug-2009.) |
⊢ ((𝐴 = 𝐵 ∧ 𝐶 = 𝐷) → (𝐴 ∖ 𝐶) = (𝐵 ∖ 𝐷)) | ||
Theorem | difeq1i 4117 | Inference adding difference to the right in a class equality. (Contributed by NM, 15-Nov-2002.) |
⊢ 𝐴 = 𝐵 ⇒ ⊢ (𝐴 ∖ 𝐶) = (𝐵 ∖ 𝐶) | ||
Theorem | difeq2i 4118 | Inference adding difference to the left in a class equality. (Contributed by NM, 15-Nov-2002.) |
⊢ 𝐴 = 𝐵 ⇒ ⊢ (𝐶 ∖ 𝐴) = (𝐶 ∖ 𝐵) | ||
Theorem | difeq12i 4119 | Equality inference for class difference. (Contributed by NM, 29-Aug-2004.) |
⊢ 𝐴 = 𝐵 & ⊢ 𝐶 = 𝐷 ⇒ ⊢ (𝐴 ∖ 𝐶) = (𝐵 ∖ 𝐷) | ||
Theorem | difeq1d 4120 | Deduction adding difference to the right in a class equality. (Contributed by NM, 15-Nov-2002.) |
⊢ (𝜑 → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → (𝐴 ∖ 𝐶) = (𝐵 ∖ 𝐶)) | ||
Theorem | difeq2d 4121 | Deduction adding difference to the left in a class equality. (Contributed by NM, 15-Nov-2002.) |
⊢ (𝜑 → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → (𝐶 ∖ 𝐴) = (𝐶 ∖ 𝐵)) | ||
Theorem | difeq12d 4122 | Equality deduction for class difference. (Contributed by FL, 29-May-2014.) |
⊢ (𝜑 → 𝐴 = 𝐵) & ⊢ (𝜑 → 𝐶 = 𝐷) ⇒ ⊢ (𝜑 → (𝐴 ∖ 𝐶) = (𝐵 ∖ 𝐷)) | ||
Theorem | difeqri 4123* | Inference from membership to difference. (Contributed by NM, 17-May-1998.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ ((𝑥 ∈ 𝐴 ∧ ¬ 𝑥 ∈ 𝐵) ↔ 𝑥 ∈ 𝐶) ⇒ ⊢ (𝐴 ∖ 𝐵) = 𝐶 | ||
Theorem | nfdif 4124 | Bound-variable hypothesis builder for class difference. (Contributed by NM, 3-Dec-2003.) (Revised by Mario Carneiro, 13-Oct-2016.) |
⊢ Ⅎ𝑥𝐴 & ⊢ Ⅎ𝑥𝐵 ⇒ ⊢ Ⅎ𝑥(𝐴 ∖ 𝐵) | ||
Theorem | eldifi 4125 | Implication of membership in a class difference. (Contributed by NM, 29-Apr-1994.) |
⊢ (𝐴 ∈ (𝐵 ∖ 𝐶) → 𝐴 ∈ 𝐵) | ||
Theorem | eldifn 4126 | Implication of membership in a class difference. (Contributed by NM, 3-May-1994.) |
⊢ (𝐴 ∈ (𝐵 ∖ 𝐶) → ¬ 𝐴 ∈ 𝐶) | ||
Theorem | elndif 4127 | A set does not belong to a class excluding it. (Contributed by NM, 27-Jun-1994.) |
⊢ (𝐴 ∈ 𝐵 → ¬ 𝐴 ∈ (𝐶 ∖ 𝐵)) | ||
Theorem | neldif 4128 | Implication of membership in a class difference. (Contributed by NM, 28-Jun-1994.) |
⊢ ((𝐴 ∈ 𝐵 ∧ ¬ 𝐴 ∈ (𝐵 ∖ 𝐶)) → 𝐴 ∈ 𝐶) | ||
Theorem | difdif 4129 | Double class difference. Exercise 11 of [TakeutiZaring] p. 22. (Contributed by NM, 17-May-1998.) |
⊢ (𝐴 ∖ (𝐵 ∖ 𝐴)) = 𝐴 | ||
Theorem | difss 4130 | Subclass relationship for class difference. Exercise 14 of [TakeutiZaring] p. 22. (Contributed by NM, 29-Apr-1994.) |
⊢ (𝐴 ∖ 𝐵) ⊆ 𝐴 | ||
Theorem | difssd 4131 | A difference of two classes is contained in the minuend. Deduction form of difss 4130. (Contributed by David Moews, 1-May-2017.) |
⊢ (𝜑 → (𝐴 ∖ 𝐵) ⊆ 𝐴) | ||
Theorem | difss2 4132 | If a class is contained in a difference, it is contained in the minuend. (Contributed by David Moews, 1-May-2017.) |
⊢ (𝐴 ⊆ (𝐵 ∖ 𝐶) → 𝐴 ⊆ 𝐵) | ||
Theorem | difss2d 4133 | If a class is contained in a difference, it is contained in the minuend. Deduction form of difss2 4132. (Contributed by David Moews, 1-May-2017.) |
⊢ (𝜑 → 𝐴 ⊆ (𝐵 ∖ 𝐶)) ⇒ ⊢ (𝜑 → 𝐴 ⊆ 𝐵) | ||
Theorem | ssdifss 4134 | Preservation of a subclass relationship by class difference. (Contributed by NM, 15-Feb-2007.) |
⊢ (𝐴 ⊆ 𝐵 → (𝐴 ∖ 𝐶) ⊆ 𝐵) | ||
Theorem | ddif 4135 | Double complement under universal class. Exercise 4.10(s) of [Mendelson] p. 231. (Contributed by NM, 8-Jan-2002.) |
⊢ (V ∖ (V ∖ 𝐴)) = 𝐴 | ||
Theorem | ssconb 4136 | Contraposition law for subsets. (Contributed by NM, 22-Mar-1998.) |
⊢ ((𝐴 ⊆ 𝐶 ∧ 𝐵 ⊆ 𝐶) → (𝐴 ⊆ (𝐶 ∖ 𝐵) ↔ 𝐵 ⊆ (𝐶 ∖ 𝐴))) | ||
Theorem | sscon 4137 | Contraposition law for subsets. Exercise 15 of [TakeutiZaring] p. 22. (Contributed by NM, 22-Mar-1998.) |
⊢ (𝐴 ⊆ 𝐵 → (𝐶 ∖ 𝐵) ⊆ (𝐶 ∖ 𝐴)) | ||
Theorem | ssdif 4138 | Difference law for subsets. (Contributed by NM, 28-May-1998.) |
⊢ (𝐴 ⊆ 𝐵 → (𝐴 ∖ 𝐶) ⊆ (𝐵 ∖ 𝐶)) | ||
Theorem | ssdifd 4139 | If 𝐴 is contained in 𝐵, then (𝐴 ∖ 𝐶) is contained in (𝐵 ∖ 𝐶). Deduction form of ssdif 4138. (Contributed by David Moews, 1-May-2017.) |
⊢ (𝜑 → 𝐴 ⊆ 𝐵) ⇒ ⊢ (𝜑 → (𝐴 ∖ 𝐶) ⊆ (𝐵 ∖ 𝐶)) | ||
Theorem | sscond 4140 | If 𝐴 is contained in 𝐵, then (𝐶 ∖ 𝐵) is contained in (𝐶 ∖ 𝐴). Deduction form of sscon 4137. (Contributed by David Moews, 1-May-2017.) |
⊢ (𝜑 → 𝐴 ⊆ 𝐵) ⇒ ⊢ (𝜑 → (𝐶 ∖ 𝐵) ⊆ (𝐶 ∖ 𝐴)) | ||
Theorem | ssdifssd 4141 | If 𝐴 is contained in 𝐵, then (𝐴 ∖ 𝐶) is also contained in 𝐵. Deduction form of ssdifss 4134. (Contributed by David Moews, 1-May-2017.) |
⊢ (𝜑 → 𝐴 ⊆ 𝐵) ⇒ ⊢ (𝜑 → (𝐴 ∖ 𝐶) ⊆ 𝐵) | ||
Theorem | ssdif2d 4142 | If 𝐴 is contained in 𝐵 and 𝐶 is contained in 𝐷, then (𝐴 ∖ 𝐷) is contained in (𝐵 ∖ 𝐶). Deduction form. (Contributed by David Moews, 1-May-2017.) |
⊢ (𝜑 → 𝐴 ⊆ 𝐵) & ⊢ (𝜑 → 𝐶 ⊆ 𝐷) ⇒ ⊢ (𝜑 → (𝐴 ∖ 𝐷) ⊆ (𝐵 ∖ 𝐶)) | ||
Theorem | raldifb 4143 | Restricted universal quantification on a class difference in terms of an implication. (Contributed by Alexander van der Vekens, 3-Jan-2018.) |
⊢ (∀𝑥 ∈ 𝐴 (𝑥 ∉ 𝐵 → 𝜑) ↔ ∀𝑥 ∈ (𝐴 ∖ 𝐵)𝜑) | ||
Theorem | rexdifi 4144 | Restricted existential quantification over a difference. (Contributed by AV, 25-Oct-2023.) |
⊢ ((∃𝑥 ∈ 𝐴 𝜑 ∧ ∀𝑥 ∈ 𝐵 ¬ 𝜑) → ∃𝑥 ∈ (𝐴 ∖ 𝐵)𝜑) | ||
Theorem | complss 4145 | Complementation reverses inclusion. (Contributed by Andrew Salmon, 15-Jul-2011.) (Proof shortened by BJ, 19-Mar-2021.) |
⊢ (𝐴 ⊆ 𝐵 ↔ (V ∖ 𝐵) ⊆ (V ∖ 𝐴)) | ||
Theorem | compleq 4146 | Two classes are equal if and only if their complements are equal. (Contributed by BJ, 19-Mar-2021.) |
⊢ (𝐴 = 𝐵 ↔ (V ∖ 𝐴) = (V ∖ 𝐵)) | ||
Theorem | elun 4147 | Expansion of membership in class union. Theorem 12 of [Suppes] p. 25. (Contributed by NM, 7-Aug-1994.) |
⊢ (𝐴 ∈ (𝐵 ∪ 𝐶) ↔ (𝐴 ∈ 𝐵 ∨ 𝐴 ∈ 𝐶)) | ||
Theorem | elunnel1 4148 | A member of a union that is not a member of the first class, is a member of the second class. (Contributed by Glauco Siliprandi, 11-Dec-2019.) |
⊢ ((𝐴 ∈ (𝐵 ∪ 𝐶) ∧ ¬ 𝐴 ∈ 𝐵) → 𝐴 ∈ 𝐶) | ||
Theorem | elunnel2 4149 | A member of a union that is not a member of the second class, is a member of the first class. (Contributed by Glauco Siliprandi, 11-Dec-2019.) |
⊢ ((𝐴 ∈ (𝐵 ∪ 𝐶) ∧ ¬ 𝐴 ∈ 𝐶) → 𝐴 ∈ 𝐵) | ||
Theorem | uneqri 4150* | Inference from membership to union. (Contributed by NM, 21-Jun-1993.) |
⊢ ((𝑥 ∈ 𝐴 ∨ 𝑥 ∈ 𝐵) ↔ 𝑥 ∈ 𝐶) ⇒ ⊢ (𝐴 ∪ 𝐵) = 𝐶 | ||
Theorem | unidm 4151 | Idempotent law for union of classes. Theorem 23 of [Suppes] p. 27. (Contributed by NM, 21-Jun-1993.) |
⊢ (𝐴 ∪ 𝐴) = 𝐴 | ||
Theorem | uncom 4152 | Commutative law for union of classes. Exercise 6 of [TakeutiZaring] p. 17. (Contributed by NM, 25-Jun-1998.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ (𝐴 ∪ 𝐵) = (𝐵 ∪ 𝐴) | ||
Theorem | equncom 4153 | If a class equals the union of two other classes, then it equals the union of those two classes commuted. equncom 4153 was automatically derived from equncomVD 43931 using the tools program translate_without_overwriting.cmd and minimizing. (Contributed by Alan Sare, 18-Feb-2012.) |
⊢ (𝐴 = (𝐵 ∪ 𝐶) ↔ 𝐴 = (𝐶 ∪ 𝐵)) | ||
Theorem | equncomi 4154 | Inference form of equncom 4153. equncomi 4154 was automatically derived from equncomiVD 43932 using the tools program translate_without_overwriting.cmd and minimizing. (Contributed by Alan Sare, 18-Feb-2012.) |
⊢ 𝐴 = (𝐵 ∪ 𝐶) ⇒ ⊢ 𝐴 = (𝐶 ∪ 𝐵) | ||
Theorem | uneq1 4155 | Equality theorem for the union of two classes. (Contributed by NM, 15-Jul-1993.) |
⊢ (𝐴 = 𝐵 → (𝐴 ∪ 𝐶) = (𝐵 ∪ 𝐶)) | ||
Theorem | uneq2 4156 | Equality theorem for the union of two classes. (Contributed by NM, 5-Aug-1993.) |
⊢ (𝐴 = 𝐵 → (𝐶 ∪ 𝐴) = (𝐶 ∪ 𝐵)) | ||
Theorem | uneq12 4157 | Equality theorem for the union of two classes. (Contributed by NM, 29-Mar-1998.) |
⊢ ((𝐴 = 𝐵 ∧ 𝐶 = 𝐷) → (𝐴 ∪ 𝐶) = (𝐵 ∪ 𝐷)) | ||
Theorem | uneq1i 4158 | Inference adding union to the right in a class equality. (Contributed by NM, 30-Aug-1993.) |
⊢ 𝐴 = 𝐵 ⇒ ⊢ (𝐴 ∪ 𝐶) = (𝐵 ∪ 𝐶) | ||
Theorem | uneq2i 4159 | Inference adding union to the left in a class equality. (Contributed by NM, 30-Aug-1993.) |
⊢ 𝐴 = 𝐵 ⇒ ⊢ (𝐶 ∪ 𝐴) = (𝐶 ∪ 𝐵) | ||
Theorem | uneq12i 4160 | Equality inference for the union of two classes. (Contributed by NM, 12-Aug-2004.) (Proof shortened by Eric Schmidt, 26-Jan-2007.) |
⊢ 𝐴 = 𝐵 & ⊢ 𝐶 = 𝐷 ⇒ ⊢ (𝐴 ∪ 𝐶) = (𝐵 ∪ 𝐷) | ||
Theorem | uneq1d 4161 | Deduction adding union to the right in a class equality. (Contributed by NM, 29-Mar-1998.) |
⊢ (𝜑 → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → (𝐴 ∪ 𝐶) = (𝐵 ∪ 𝐶)) | ||
Theorem | uneq2d 4162 | Deduction adding union to the left in a class equality. (Contributed by NM, 29-Mar-1998.) |
⊢ (𝜑 → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → (𝐶 ∪ 𝐴) = (𝐶 ∪ 𝐵)) | ||
Theorem | uneq12d 4163 | Equality deduction for the union of two classes. (Contributed by NM, 29-Sep-2004.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ (𝜑 → 𝐴 = 𝐵) & ⊢ (𝜑 → 𝐶 = 𝐷) ⇒ ⊢ (𝜑 → (𝐴 ∪ 𝐶) = (𝐵 ∪ 𝐷)) | ||
Theorem | nfun 4164 | Bound-variable hypothesis builder for the union of classes. (Contributed by NM, 15-Sep-2003.) (Revised by Mario Carneiro, 14-Oct-2016.) |
⊢ Ⅎ𝑥𝐴 & ⊢ Ⅎ𝑥𝐵 ⇒ ⊢ Ⅎ𝑥(𝐴 ∪ 𝐵) | ||
Theorem | unass 4165 | Associative law for union of classes. Exercise 8 of [TakeutiZaring] p. 17. (Contributed by NM, 3-May-1994.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ ((𝐴 ∪ 𝐵) ∪ 𝐶) = (𝐴 ∪ (𝐵 ∪ 𝐶)) | ||
Theorem | un12 4166 | A rearrangement of union. (Contributed by NM, 12-Aug-2004.) |
⊢ (𝐴 ∪ (𝐵 ∪ 𝐶)) = (𝐵 ∪ (𝐴 ∪ 𝐶)) | ||
Theorem | un23 4167 | A rearrangement of union. (Contributed by NM, 12-Aug-2004.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ ((𝐴 ∪ 𝐵) ∪ 𝐶) = ((𝐴 ∪ 𝐶) ∪ 𝐵) | ||
Theorem | un4 4168 | A rearrangement of the union of 4 classes. (Contributed by NM, 12-Aug-2004.) |
⊢ ((𝐴 ∪ 𝐵) ∪ (𝐶 ∪ 𝐷)) = ((𝐴 ∪ 𝐶) ∪ (𝐵 ∪ 𝐷)) | ||
Theorem | unundi 4169 | Union distributes over itself. (Contributed by NM, 17-Aug-2004.) |
⊢ (𝐴 ∪ (𝐵 ∪ 𝐶)) = ((𝐴 ∪ 𝐵) ∪ (𝐴 ∪ 𝐶)) | ||
Theorem | unundir 4170 | Union distributes over itself. (Contributed by NM, 17-Aug-2004.) |
⊢ ((𝐴 ∪ 𝐵) ∪ 𝐶) = ((𝐴 ∪ 𝐶) ∪ (𝐵 ∪ 𝐶)) | ||
Theorem | ssun1 4171 | Subclass relationship for union of classes. Theorem 25 of [Suppes] p. 27. (Contributed by NM, 5-Aug-1993.) |
⊢ 𝐴 ⊆ (𝐴 ∪ 𝐵) | ||
Theorem | ssun2 4172 | Subclass relationship for union of classes. (Contributed by NM, 30-Aug-1993.) |
⊢ 𝐴 ⊆ (𝐵 ∪ 𝐴) | ||
Theorem | ssun3 4173 | Subclass law for union of classes. (Contributed by NM, 5-Aug-1993.) |
⊢ (𝐴 ⊆ 𝐵 → 𝐴 ⊆ (𝐵 ∪ 𝐶)) | ||
Theorem | ssun4 4174 | Subclass law for union of classes. (Contributed by NM, 14-Aug-1994.) |
⊢ (𝐴 ⊆ 𝐵 → 𝐴 ⊆ (𝐶 ∪ 𝐵)) | ||
Theorem | elun1 4175 | Membership law for union of classes. (Contributed by NM, 5-Aug-1993.) |
⊢ (𝐴 ∈ 𝐵 → 𝐴 ∈ (𝐵 ∪ 𝐶)) | ||
Theorem | elun2 4176 | Membership law for union of classes. (Contributed by NM, 30-Aug-1993.) |
⊢ (𝐴 ∈ 𝐵 → 𝐴 ∈ (𝐶 ∪ 𝐵)) | ||
Theorem | elunant 4177 | A statement is true for every element of the union of a pair of classes if and only if it is true for every element of the first class and for every element of the second class. (Contributed by BTernaryTau, 27-Sep-2023.) |
⊢ ((𝐶 ∈ (𝐴 ∪ 𝐵) → 𝜑) ↔ ((𝐶 ∈ 𝐴 → 𝜑) ∧ (𝐶 ∈ 𝐵 → 𝜑))) | ||
Theorem | unss1 4178 | Subclass law for union of classes. (Contributed by NM, 14-Oct-1999.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ (𝐴 ⊆ 𝐵 → (𝐴 ∪ 𝐶) ⊆ (𝐵 ∪ 𝐶)) | ||
Theorem | ssequn1 4179 | A relationship between subclass and union. Theorem 26 of [Suppes] p. 27. (Contributed by NM, 30-Aug-1993.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ (𝐴 ⊆ 𝐵 ↔ (𝐴 ∪ 𝐵) = 𝐵) | ||
Theorem | unss2 4180 | Subclass law for union of classes. Exercise 7 of [TakeutiZaring] p. 18. (Contributed by NM, 14-Oct-1999.) |
⊢ (𝐴 ⊆ 𝐵 → (𝐶 ∪ 𝐴) ⊆ (𝐶 ∪ 𝐵)) | ||
Theorem | unss12 4181 | Subclass law for union of classes. (Contributed by NM, 2-Jun-2004.) |
⊢ ((𝐴 ⊆ 𝐵 ∧ 𝐶 ⊆ 𝐷) → (𝐴 ∪ 𝐶) ⊆ (𝐵 ∪ 𝐷)) | ||
Theorem | ssequn2 4182 | A relationship between subclass and union. (Contributed by NM, 13-Jun-1994.) |
⊢ (𝐴 ⊆ 𝐵 ↔ (𝐵 ∪ 𝐴) = 𝐵) | ||
Theorem | unss 4183 | The union of two subclasses is a subclass. Theorem 27 of [Suppes] p. 27 and its converse. (Contributed by NM, 11-Jun-2004.) |
⊢ ((𝐴 ⊆ 𝐶 ∧ 𝐵 ⊆ 𝐶) ↔ (𝐴 ∪ 𝐵) ⊆ 𝐶) | ||
Theorem | unssi 4184 | An inference showing the union of two subclasses is a subclass. (Contributed by Raph Levien, 10-Dec-2002.) |
⊢ 𝐴 ⊆ 𝐶 & ⊢ 𝐵 ⊆ 𝐶 ⇒ ⊢ (𝐴 ∪ 𝐵) ⊆ 𝐶 | ||
Theorem | unssd 4185 | A deduction showing the union of two subclasses is a subclass. (Contributed by Jonathan Ben-Naim, 3-Jun-2011.) |
⊢ (𝜑 → 𝐴 ⊆ 𝐶) & ⊢ (𝜑 → 𝐵 ⊆ 𝐶) ⇒ ⊢ (𝜑 → (𝐴 ∪ 𝐵) ⊆ 𝐶) | ||
Theorem | unssad 4186 | If (𝐴 ∪ 𝐵) is contained in 𝐶, so is 𝐴. One-way deduction form of unss 4183. Partial converse of unssd 4185. (Contributed by David Moews, 1-May-2017.) |
⊢ (𝜑 → (𝐴 ∪ 𝐵) ⊆ 𝐶) ⇒ ⊢ (𝜑 → 𝐴 ⊆ 𝐶) | ||
Theorem | unssbd 4187 | If (𝐴 ∪ 𝐵) is contained in 𝐶, so is 𝐵. One-way deduction form of unss 4183. Partial converse of unssd 4185. (Contributed by David Moews, 1-May-2017.) |
⊢ (𝜑 → (𝐴 ∪ 𝐵) ⊆ 𝐶) ⇒ ⊢ (𝜑 → 𝐵 ⊆ 𝐶) | ||
Theorem | ssun 4188 | A condition that implies inclusion in the union of two classes. (Contributed by NM, 23-Nov-2003.) |
⊢ ((𝐴 ⊆ 𝐵 ∨ 𝐴 ⊆ 𝐶) → 𝐴 ⊆ (𝐵 ∪ 𝐶)) | ||
Theorem | rexun 4189 | Restricted existential quantification over union. (Contributed by Jeff Madsen, 5-Jan-2011.) |
⊢ (∃𝑥 ∈ (𝐴 ∪ 𝐵)𝜑 ↔ (∃𝑥 ∈ 𝐴 𝜑 ∨ ∃𝑥 ∈ 𝐵 𝜑)) | ||
Theorem | ralunb 4190 | Restricted quantification over a union. (Contributed by Scott Fenton, 12-Apr-2011.) (Proof shortened by Andrew Salmon, 29-Jun-2011.) |
⊢ (∀𝑥 ∈ (𝐴 ∪ 𝐵)𝜑 ↔ (∀𝑥 ∈ 𝐴 𝜑 ∧ ∀𝑥 ∈ 𝐵 𝜑)) | ||
Theorem | ralun 4191 | Restricted quantification over union. (Contributed by Jeff Madsen, 2-Sep-2009.) |
⊢ ((∀𝑥 ∈ 𝐴 𝜑 ∧ ∀𝑥 ∈ 𝐵 𝜑) → ∀𝑥 ∈ (𝐴 ∪ 𝐵)𝜑) | ||
Theorem | elini 4192 | Membership in an intersection of two classes. (Contributed by Glauco Siliprandi, 17-Aug-2020.) |
⊢ 𝐴 ∈ 𝐵 & ⊢ 𝐴 ∈ 𝐶 ⇒ ⊢ 𝐴 ∈ (𝐵 ∩ 𝐶) | ||
Theorem | elind 4193 | Deduce membership in an intersection of two classes. (Contributed by Jonathan Ben-Naim, 3-Jun-2011.) |
⊢ (𝜑 → 𝑋 ∈ 𝐴) & ⊢ (𝜑 → 𝑋 ∈ 𝐵) ⇒ ⊢ (𝜑 → 𝑋 ∈ (𝐴 ∩ 𝐵)) | ||
Theorem | elinel1 4194 | Membership in an intersection implies membership in the first set. (Contributed by Glauco Siliprandi, 11-Dec-2019.) |
⊢ (𝐴 ∈ (𝐵 ∩ 𝐶) → 𝐴 ∈ 𝐵) | ||
Theorem | elinel2 4195 | Membership in an intersection implies membership in the second set. (Contributed by Glauco Siliprandi, 11-Dec-2019.) |
⊢ (𝐴 ∈ (𝐵 ∩ 𝐶) → 𝐴 ∈ 𝐶) | ||
Theorem | elin2 4196 | Membership in a class defined as an intersection. (Contributed by Stefan O'Rear, 29-Mar-2015.) |
⊢ 𝑋 = (𝐵 ∩ 𝐶) ⇒ ⊢ (𝐴 ∈ 𝑋 ↔ (𝐴 ∈ 𝐵 ∧ 𝐴 ∈ 𝐶)) | ||
Theorem | elin1d 4197 | Elementhood in the first set of an intersection - deduction version. (Contributed by Thierry Arnoux, 3-May-2020.) |
⊢ (𝜑 → 𝑋 ∈ (𝐴 ∩ 𝐵)) ⇒ ⊢ (𝜑 → 𝑋 ∈ 𝐴) | ||
Theorem | elin2d 4198 | Elementhood in the first set of an intersection - deduction version. (Contributed by Thierry Arnoux, 3-May-2020.) |
⊢ (𝜑 → 𝑋 ∈ (𝐴 ∩ 𝐵)) ⇒ ⊢ (𝜑 → 𝑋 ∈ 𝐵) | ||
Theorem | elin3 4199 | Membership in a class defined as a ternary intersection. (Contributed by Stefan O'Rear, 29-Mar-2015.) |
⊢ 𝑋 = ((𝐵 ∩ 𝐶) ∩ 𝐷) ⇒ ⊢ (𝐴 ∈ 𝑋 ↔ (𝐴 ∈ 𝐵 ∧ 𝐴 ∈ 𝐶 ∧ 𝐴 ∈ 𝐷)) | ||
Theorem | incom 4200 | Commutative law for intersection of classes. Exercise 7 of [TakeutiZaring] p. 17. (Contributed by NM, 21-Jun-1993.) (Proof shortened by SN, 12-Dec-2023.) |
⊢ (𝐴 ∩ 𝐵) = (𝐵 ∩ 𝐴) |
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