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| Type | Label | Description |
|---|---|---|
| Statement | ||
| Theorem | ssdifssd 4101 | If 𝐴 is contained in 𝐵, then (𝐴 ∖ 𝐶) is also contained in 𝐵. Deduction form of ssdifss 4094. (Contributed by David Moews, 1-May-2017.) |
| ⊢ (𝜑 → 𝐴 ⊆ 𝐵) ⇒ ⊢ (𝜑 → (𝐴 ∖ 𝐶) ⊆ 𝐵) | ||
| Theorem | ssdif2d 4102 | If 𝐴 is contained in 𝐵 and 𝐶 is contained in 𝐷, then (𝐴 ∖ 𝐷) is contained in (𝐵 ∖ 𝐶). Deduction form. (Contributed by David Moews, 1-May-2017.) |
| ⊢ (𝜑 → 𝐴 ⊆ 𝐵) & ⊢ (𝜑 → 𝐶 ⊆ 𝐷) ⇒ ⊢ (𝜑 → (𝐴 ∖ 𝐷) ⊆ (𝐵 ∖ 𝐶)) | ||
| Theorem | raldifb 4103 | Restricted universal quantification on a class difference in terms of an implication. (Contributed by Alexander van der Vekens, 3-Jan-2018.) |
| ⊢ (∀𝑥 ∈ 𝐴 (𝑥 ∉ 𝐵 → 𝜑) ↔ ∀𝑥 ∈ (𝐴 ∖ 𝐵)𝜑) | ||
| Theorem | rexdifi 4104 | Restricted existential quantification over a difference. (Contributed by AV, 25-Oct-2023.) |
| ⊢ ((∃𝑥 ∈ 𝐴 𝜑 ∧ ∀𝑥 ∈ 𝐵 ¬ 𝜑) → ∃𝑥 ∈ (𝐴 ∖ 𝐵)𝜑) | ||
| Theorem | complss 4105 | Complementation reverses inclusion. (Contributed by Andrew Salmon, 15-Jul-2011.) (Proof shortened by BJ, 19-Mar-2021.) |
| ⊢ (𝐴 ⊆ 𝐵 ↔ (V ∖ 𝐵) ⊆ (V ∖ 𝐴)) | ||
| Theorem | compleq 4106 | Two classes are equal if and only if their complements are equal. (Contributed by BJ, 19-Mar-2021.) |
| ⊢ (𝐴 = 𝐵 ↔ (V ∖ 𝐴) = (V ∖ 𝐵)) | ||
| Theorem | elun 4107 | Expansion of membership in class union. Theorem 12 of [Suppes] p. 25. (Contributed by NM, 7-Aug-1994.) |
| ⊢ (𝐴 ∈ (𝐵 ∪ 𝐶) ↔ (𝐴 ∈ 𝐵 ∨ 𝐴 ∈ 𝐶)) | ||
| Theorem | elunnel1 4108 | A member of a union that is not a member of the first class, is a member of the second class. (Contributed by Glauco Siliprandi, 11-Dec-2019.) |
| ⊢ ((𝐴 ∈ (𝐵 ∪ 𝐶) ∧ ¬ 𝐴 ∈ 𝐵) → 𝐴 ∈ 𝐶) | ||
| Theorem | elunnel2 4109 | A member of a union that is not a member of the second class, is a member of the first class. (Contributed by Glauco Siliprandi, 11-Dec-2019.) |
| ⊢ ((𝐴 ∈ (𝐵 ∪ 𝐶) ∧ ¬ 𝐴 ∈ 𝐶) → 𝐴 ∈ 𝐵) | ||
| Theorem | uneqri 4110* | Inference from membership to union. (Contributed by NM, 21-Jun-1993.) |
| ⊢ ((𝑥 ∈ 𝐴 ∨ 𝑥 ∈ 𝐵) ↔ 𝑥 ∈ 𝐶) ⇒ ⊢ (𝐴 ∪ 𝐵) = 𝐶 | ||
| Theorem | unidm 4111 | Idempotent law for union of classes. Theorem 23 of [Suppes] p. 27. (Contributed by NM, 21-Jun-1993.) |
| ⊢ (𝐴 ∪ 𝐴) = 𝐴 | ||
| Theorem | uncom 4112 | Commutative law for union of classes. Exercise 6 of [TakeutiZaring] p. 17. (Contributed by NM, 25-Jun-1998.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
| ⊢ (𝐴 ∪ 𝐵) = (𝐵 ∪ 𝐴) | ||
| Theorem | equncom 4113 | If a class equals the union of two other classes, then it equals the union of those two classes commuted. equncom 4113 was automatically derived from equncomVD 45217 using the tools program translate_without_overwriting.cmd and minimizing. (Contributed by Alan Sare, 18-Feb-2012.) |
| ⊢ (𝐴 = (𝐵 ∪ 𝐶) ↔ 𝐴 = (𝐶 ∪ 𝐵)) | ||
| Theorem | equncomi 4114 | Inference form of equncom 4113. equncomi 4114 was automatically derived from equncomiVD 45218 using the tools program translate_without_overwriting.cmd and minimizing. (Contributed by Alan Sare, 18-Feb-2012.) |
| ⊢ 𝐴 = (𝐵 ∪ 𝐶) ⇒ ⊢ 𝐴 = (𝐶 ∪ 𝐵) | ||
| Theorem | uneq1 4115 | Equality theorem for the union of two classes. (Contributed by NM, 15-Jul-1993.) |
| ⊢ (𝐴 = 𝐵 → (𝐴 ∪ 𝐶) = (𝐵 ∪ 𝐶)) | ||
| Theorem | uneq2 4116 | Equality theorem for the union of two classes. (Contributed by NM, 5-Aug-1993.) |
| ⊢ (𝐴 = 𝐵 → (𝐶 ∪ 𝐴) = (𝐶 ∪ 𝐵)) | ||
| Theorem | uneq12 4117 | Equality theorem for the union of two classes. (Contributed by NM, 29-Mar-1998.) |
| ⊢ ((𝐴 = 𝐵 ∧ 𝐶 = 𝐷) → (𝐴 ∪ 𝐶) = (𝐵 ∪ 𝐷)) | ||
| Theorem | uneq1i 4118 | Inference adding union to the right in a class equality. (Contributed by NM, 30-Aug-1993.) |
| ⊢ 𝐴 = 𝐵 ⇒ ⊢ (𝐴 ∪ 𝐶) = (𝐵 ∪ 𝐶) | ||
| Theorem | uneq2i 4119 | Inference adding union to the left in a class equality. (Contributed by NM, 30-Aug-1993.) |
| ⊢ 𝐴 = 𝐵 ⇒ ⊢ (𝐶 ∪ 𝐴) = (𝐶 ∪ 𝐵) | ||
| Theorem | uneq12i 4120 | Equality inference for the union of two classes. (Contributed by NM, 12-Aug-2004.) (Proof shortened by Eric Schmidt, 26-Jan-2007.) |
| ⊢ 𝐴 = 𝐵 & ⊢ 𝐶 = 𝐷 ⇒ ⊢ (𝐴 ∪ 𝐶) = (𝐵 ∪ 𝐷) | ||
| Theorem | uneq1d 4121 | Deduction adding union to the right in a class equality. (Contributed by NM, 29-Mar-1998.) |
| ⊢ (𝜑 → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → (𝐴 ∪ 𝐶) = (𝐵 ∪ 𝐶)) | ||
| Theorem | uneq2d 4122 | Deduction adding union to the left in a class equality. (Contributed by NM, 29-Mar-1998.) |
| ⊢ (𝜑 → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → (𝐶 ∪ 𝐴) = (𝐶 ∪ 𝐵)) | ||
| Theorem | uneq12d 4123 | Equality deduction for the union of two classes. (Contributed by NM, 29-Sep-2004.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
| ⊢ (𝜑 → 𝐴 = 𝐵) & ⊢ (𝜑 → 𝐶 = 𝐷) ⇒ ⊢ (𝜑 → (𝐴 ∪ 𝐶) = (𝐵 ∪ 𝐷)) | ||
| Theorem | nfun 4124 | Bound-variable hypothesis builder for the union of classes. (Contributed by NM, 15-Sep-2003.) (Revised by Mario Carneiro, 14-Oct-2016.) Avoid ax-10 2147, ax-11 2163, ax-12 2185. (Revised by SN, 14-May-2025.) |
| ⊢ Ⅎ𝑥𝐴 & ⊢ Ⅎ𝑥𝐵 ⇒ ⊢ Ⅎ𝑥(𝐴 ∪ 𝐵) | ||
| Theorem | nfunOLD 4125 | Obsolete version of nfun 4124 as of 14-May-2025. (Contributed by NM, 15-Sep-2003.) (Revised by Mario Carneiro, 14-Oct-2016.) (Proof modification is discouraged.) (New usage is discouraged.) |
| ⊢ Ⅎ𝑥𝐴 & ⊢ Ⅎ𝑥𝐵 ⇒ ⊢ Ⅎ𝑥(𝐴 ∪ 𝐵) | ||
| Theorem | unass 4126 | Associative law for union of classes. Exercise 8 of [TakeutiZaring] p. 17. (Contributed by NM, 3-May-1994.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
| ⊢ ((𝐴 ∪ 𝐵) ∪ 𝐶) = (𝐴 ∪ (𝐵 ∪ 𝐶)) | ||
| Theorem | un12 4127 | A rearrangement of union. (Contributed by NM, 12-Aug-2004.) |
| ⊢ (𝐴 ∪ (𝐵 ∪ 𝐶)) = (𝐵 ∪ (𝐴 ∪ 𝐶)) | ||
| Theorem | un23 4128 | A rearrangement of union. (Contributed by NM, 12-Aug-2004.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
| ⊢ ((𝐴 ∪ 𝐵) ∪ 𝐶) = ((𝐴 ∪ 𝐶) ∪ 𝐵) | ||
| Theorem | un4 4129 | A rearrangement of the union of 4 classes. (Contributed by NM, 12-Aug-2004.) |
| ⊢ ((𝐴 ∪ 𝐵) ∪ (𝐶 ∪ 𝐷)) = ((𝐴 ∪ 𝐶) ∪ (𝐵 ∪ 𝐷)) | ||
| Theorem | unundi 4130 | Union distributes over itself. (Contributed by NM, 17-Aug-2004.) |
| ⊢ (𝐴 ∪ (𝐵 ∪ 𝐶)) = ((𝐴 ∪ 𝐵) ∪ (𝐴 ∪ 𝐶)) | ||
| Theorem | unundir 4131 | Union distributes over itself. (Contributed by NM, 17-Aug-2004.) |
| ⊢ ((𝐴 ∪ 𝐵) ∪ 𝐶) = ((𝐴 ∪ 𝐶) ∪ (𝐵 ∪ 𝐶)) | ||
| Theorem | ssun1 4132 | Subclass relationship for union of classes. Theorem 25 of [Suppes] p. 27. (Contributed by NM, 5-Aug-1993.) |
| ⊢ 𝐴 ⊆ (𝐴 ∪ 𝐵) | ||
| Theorem | ssun2 4133 | Subclass relationship for union of classes. (Contributed by NM, 30-Aug-1993.) |
| ⊢ 𝐴 ⊆ (𝐵 ∪ 𝐴) | ||
| Theorem | ssun3 4134 | Subclass law for union of classes. (Contributed by NM, 5-Aug-1993.) |
| ⊢ (𝐴 ⊆ 𝐵 → 𝐴 ⊆ (𝐵 ∪ 𝐶)) | ||
| Theorem | ssun4 4135 | Subclass law for union of classes. (Contributed by NM, 14-Aug-1994.) |
| ⊢ (𝐴 ⊆ 𝐵 → 𝐴 ⊆ (𝐶 ∪ 𝐵)) | ||
| Theorem | elun1 4136 | Membership law for union of classes. (Contributed by NM, 5-Aug-1993.) |
| ⊢ (𝐴 ∈ 𝐵 → 𝐴 ∈ (𝐵 ∪ 𝐶)) | ||
| Theorem | elun2 4137 | Membership law for union of classes. (Contributed by NM, 30-Aug-1993.) |
| ⊢ (𝐴 ∈ 𝐵 → 𝐴 ∈ (𝐶 ∪ 𝐵)) | ||
| Theorem | elunant 4138 | A statement is true for every element of the union of a pair of classes if and only if it is true for every element of the first class and for every element of the second class. (Contributed by BTernaryTau, 27-Sep-2023.) |
| ⊢ ((𝐶 ∈ (𝐴 ∪ 𝐵) → 𝜑) ↔ ((𝐶 ∈ 𝐴 → 𝜑) ∧ (𝐶 ∈ 𝐵 → 𝜑))) | ||
| Theorem | unss1 4139 | Subclass law for union of classes. (Contributed by NM, 14-Oct-1999.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
| ⊢ (𝐴 ⊆ 𝐵 → (𝐴 ∪ 𝐶) ⊆ (𝐵 ∪ 𝐶)) | ||
| Theorem | ssequn1 4140 | A relationship between subclass and union. Theorem 26 of [Suppes] p. 27. (Contributed by NM, 30-Aug-1993.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
| ⊢ (𝐴 ⊆ 𝐵 ↔ (𝐴 ∪ 𝐵) = 𝐵) | ||
| Theorem | unss2 4141 | Subclass law for union of classes. Exercise 7 of [TakeutiZaring] p. 18. (Contributed by NM, 14-Oct-1999.) |
| ⊢ (𝐴 ⊆ 𝐵 → (𝐶 ∪ 𝐴) ⊆ (𝐶 ∪ 𝐵)) | ||
| Theorem | unss12 4142 | Subclass law for union of classes. (Contributed by NM, 2-Jun-2004.) |
| ⊢ ((𝐴 ⊆ 𝐵 ∧ 𝐶 ⊆ 𝐷) → (𝐴 ∪ 𝐶) ⊆ (𝐵 ∪ 𝐷)) | ||
| Theorem | ssequn2 4143 | A relationship between subclass and union. (Contributed by NM, 13-Jun-1994.) |
| ⊢ (𝐴 ⊆ 𝐵 ↔ (𝐵 ∪ 𝐴) = 𝐵) | ||
| Theorem | unss 4144 | The union of two subclasses is a subclass. Theorem 27 of [Suppes] p. 27 and its converse. (Contributed by NM, 11-Jun-2004.) |
| ⊢ ((𝐴 ⊆ 𝐶 ∧ 𝐵 ⊆ 𝐶) ↔ (𝐴 ∪ 𝐵) ⊆ 𝐶) | ||
| Theorem | unssi 4145 | An inference showing the union of two subclasses is a subclass. (Contributed by Raph Levien, 10-Dec-2002.) |
| ⊢ 𝐴 ⊆ 𝐶 & ⊢ 𝐵 ⊆ 𝐶 ⇒ ⊢ (𝐴 ∪ 𝐵) ⊆ 𝐶 | ||
| Theorem | unssd 4146 | A deduction showing the union of two subclasses is a subclass. (Contributed by Jonathan Ben-Naim, 3-Jun-2011.) |
| ⊢ (𝜑 → 𝐴 ⊆ 𝐶) & ⊢ (𝜑 → 𝐵 ⊆ 𝐶) ⇒ ⊢ (𝜑 → (𝐴 ∪ 𝐵) ⊆ 𝐶) | ||
| Theorem | unssad 4147 | If (𝐴 ∪ 𝐵) is contained in 𝐶, so is 𝐴. One-way deduction form of unss 4144. Partial converse of unssd 4146. (Contributed by David Moews, 1-May-2017.) |
| ⊢ (𝜑 → (𝐴 ∪ 𝐵) ⊆ 𝐶) ⇒ ⊢ (𝜑 → 𝐴 ⊆ 𝐶) | ||
| Theorem | unssbd 4148 | If (𝐴 ∪ 𝐵) is contained in 𝐶, so is 𝐵. One-way deduction form of unss 4144. Partial converse of unssd 4146. (Contributed by David Moews, 1-May-2017.) |
| ⊢ (𝜑 → (𝐴 ∪ 𝐵) ⊆ 𝐶) ⇒ ⊢ (𝜑 → 𝐵 ⊆ 𝐶) | ||
| Theorem | ssun 4149 | A condition that implies inclusion in the union of two classes. (Contributed by NM, 23-Nov-2003.) |
| ⊢ ((𝐴 ⊆ 𝐵 ∨ 𝐴 ⊆ 𝐶) → 𝐴 ⊆ (𝐵 ∪ 𝐶)) | ||
| Theorem | rexun 4150 | Restricted existential quantification over union. (Contributed by Jeff Madsen, 5-Jan-2011.) |
| ⊢ (∃𝑥 ∈ (𝐴 ∪ 𝐵)𝜑 ↔ (∃𝑥 ∈ 𝐴 𝜑 ∨ ∃𝑥 ∈ 𝐵 𝜑)) | ||
| Theorem | ralunb 4151 | Restricted quantification over a union. (Contributed by Scott Fenton, 12-Apr-2011.) (Proof shortened by Andrew Salmon, 29-Jun-2011.) |
| ⊢ (∀𝑥 ∈ (𝐴 ∪ 𝐵)𝜑 ↔ (∀𝑥 ∈ 𝐴 𝜑 ∧ ∀𝑥 ∈ 𝐵 𝜑)) | ||
| Theorem | ralun 4152 | Restricted quantification over union. (Contributed by Jeff Madsen, 2-Sep-2009.) |
| ⊢ ((∀𝑥 ∈ 𝐴 𝜑 ∧ ∀𝑥 ∈ 𝐵 𝜑) → ∀𝑥 ∈ (𝐴 ∪ 𝐵)𝜑) | ||
| Theorem | elini 4153 | Membership in an intersection of two classes. (Contributed by Glauco Siliprandi, 17-Aug-2020.) |
| ⊢ 𝐴 ∈ 𝐵 & ⊢ 𝐴 ∈ 𝐶 ⇒ ⊢ 𝐴 ∈ (𝐵 ∩ 𝐶) | ||
| Theorem | elind 4154 | Deduce membership in an intersection of two classes. (Contributed by Jonathan Ben-Naim, 3-Jun-2011.) |
| ⊢ (𝜑 → 𝑋 ∈ 𝐴) & ⊢ (𝜑 → 𝑋 ∈ 𝐵) ⇒ ⊢ (𝜑 → 𝑋 ∈ (𝐴 ∩ 𝐵)) | ||
| Theorem | elinel1 4155 | Membership in an intersection implies membership in the first set. (Contributed by Glauco Siliprandi, 11-Dec-2019.) |
| ⊢ (𝐴 ∈ (𝐵 ∩ 𝐶) → 𝐴 ∈ 𝐵) | ||
| Theorem | elinel2 4156 | Membership in an intersection implies membership in the second set. (Contributed by Glauco Siliprandi, 11-Dec-2019.) |
| ⊢ (𝐴 ∈ (𝐵 ∩ 𝐶) → 𝐴 ∈ 𝐶) | ||
| Theorem | elin2 4157 | Membership in a class defined as an intersection. (Contributed by Stefan O'Rear, 29-Mar-2015.) |
| ⊢ 𝑋 = (𝐵 ∩ 𝐶) ⇒ ⊢ (𝐴 ∈ 𝑋 ↔ (𝐴 ∈ 𝐵 ∧ 𝐴 ∈ 𝐶)) | ||
| Theorem | elin1d 4158 | Elementhood in the first set of an intersection - deduction version. (Contributed by Thierry Arnoux, 3-May-2020.) |
| ⊢ (𝜑 → 𝑋 ∈ (𝐴 ∩ 𝐵)) ⇒ ⊢ (𝜑 → 𝑋 ∈ 𝐴) | ||
| Theorem | elin2d 4159 | Elementhood in the first set of an intersection - deduction version. (Contributed by Thierry Arnoux, 3-May-2020.) |
| ⊢ (𝜑 → 𝑋 ∈ (𝐴 ∩ 𝐵)) ⇒ ⊢ (𝜑 → 𝑋 ∈ 𝐵) | ||
| Theorem | elin3 4160 | Membership in a class defined as a ternary intersection. (Contributed by Stefan O'Rear, 29-Mar-2015.) |
| ⊢ 𝑋 = ((𝐵 ∩ 𝐶) ∩ 𝐷) ⇒ ⊢ (𝐴 ∈ 𝑋 ↔ (𝐴 ∈ 𝐵 ∧ 𝐴 ∈ 𝐶 ∧ 𝐴 ∈ 𝐷)) | ||
| Theorem | nel1nelin 4161 | Membership in an intersection implies membership in the first set. (Contributed by Glauco Siliprandi, 2-Jan-2022.) |
| ⊢ (¬ 𝐴 ∈ 𝐵 → ¬ 𝐴 ∈ (𝐵 ∩ 𝐶)) | ||
| Theorem | nel2nelin 4162 | Membership in an intersection implies membership in the second set. (Contributed by Glauco Siliprandi, 2-Jan-2022.) |
| ⊢ (¬ 𝐴 ∈ 𝐶 → ¬ 𝐴 ∈ (𝐵 ∩ 𝐶)) | ||
| Theorem | incom 4163 | Commutative law for intersection of classes. Exercise 7 of [TakeutiZaring] p. 17. (Contributed by NM, 21-Jun-1993.) (Proof shortened by SN, 12-Dec-2023.) |
| ⊢ (𝐴 ∩ 𝐵) = (𝐵 ∩ 𝐴) | ||
| Theorem | ineqcom 4164 | Two ways of expressing that two classes have a given intersection. This is often used when that given intersection is the empty set, in which case the statement displays two ways of expressing that two classes are disjoint (when 𝐶 = ∅: ((𝐴 ∩ 𝐵) = ∅ ↔ (𝐵 ∩ 𝐴) = ∅)). (Contributed by Peter Mazsa, 22-Mar-2017.) |
| ⊢ ((𝐴 ∩ 𝐵) = 𝐶 ↔ (𝐵 ∩ 𝐴) = 𝐶) | ||
| Theorem | ineqcomi 4165 | Two ways of expressing that two classes have a given intersection. Inference form of ineqcom 4164. Disjointness inference when 𝐶 = ∅. (Contributed by Peter Mazsa, 26-Mar-2017.) (Proof shortened by SN, 20-Sep-2024.) |
| ⊢ (𝐴 ∩ 𝐵) = 𝐶 ⇒ ⊢ (𝐵 ∩ 𝐴) = 𝐶 | ||
| Theorem | ineqri 4166* | Inference from membership to intersection. (Contributed by NM, 21-Jun-1993.) |
| ⊢ ((𝑥 ∈ 𝐴 ∧ 𝑥 ∈ 𝐵) ↔ 𝑥 ∈ 𝐶) ⇒ ⊢ (𝐴 ∩ 𝐵) = 𝐶 | ||
| Theorem | ineq1 4167 | Equality theorem for intersection of two classes. (Contributed by NM, 14-Dec-1993.) (Proof shortened by SN, 20-Sep-2023.) |
| ⊢ (𝐴 = 𝐵 → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐶)) | ||
| Theorem | ineq2 4168 | Equality theorem for intersection of two classes. (Contributed by NM, 26-Dec-1993.) |
| ⊢ (𝐴 = 𝐵 → (𝐶 ∩ 𝐴) = (𝐶 ∩ 𝐵)) | ||
| Theorem | ineq12 4169 | Equality theorem for intersection of two classes. (Contributed by NM, 8-May-1994.) |
| ⊢ ((𝐴 = 𝐵 ∧ 𝐶 = 𝐷) → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐷)) | ||
| Theorem | ineq1i 4170 | Equality inference for intersection of two classes. (Contributed by NM, 26-Dec-1993.) |
| ⊢ 𝐴 = 𝐵 ⇒ ⊢ (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐶) | ||
| Theorem | ineq2i 4171 | Equality inference for intersection of two classes. (Contributed by NM, 26-Dec-1993.) |
| ⊢ 𝐴 = 𝐵 ⇒ ⊢ (𝐶 ∩ 𝐴) = (𝐶 ∩ 𝐵) | ||
| Theorem | ineq12i 4172 | Equality inference for intersection of two classes. (Contributed by NM, 24-Jun-2004.) (Proof shortened by Eric Schmidt, 26-Jan-2007.) |
| ⊢ 𝐴 = 𝐵 & ⊢ 𝐶 = 𝐷 ⇒ ⊢ (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐷) | ||
| Theorem | ineq1d 4173 | Equality deduction for intersection of two classes. (Contributed by NM, 10-Apr-1994.) |
| ⊢ (𝜑 → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐶)) | ||
| Theorem | ineq2d 4174 | Equality deduction for intersection of two classes. (Contributed by NM, 10-Apr-1994.) |
| ⊢ (𝜑 → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → (𝐶 ∩ 𝐴) = (𝐶 ∩ 𝐵)) | ||
| Theorem | ineq12d 4175 | Equality deduction for intersection of two classes. (Contributed by NM, 24-Jun-2004.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
| ⊢ (𝜑 → 𝐴 = 𝐵) & ⊢ (𝜑 → 𝐶 = 𝐷) ⇒ ⊢ (𝜑 → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐷)) | ||
| Theorem | ineqan12d 4176 | Equality deduction for intersection of two classes. (Contributed by NM, 7-Feb-2007.) |
| ⊢ (𝜑 → 𝐴 = 𝐵) & ⊢ (𝜓 → 𝐶 = 𝐷) ⇒ ⊢ ((𝜑 ∧ 𝜓) → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐷)) | ||
| Theorem | sseqin2 4177 | A relationship between subclass and intersection. Similar to Exercise 9 of [TakeutiZaring] p. 18. (Contributed by NM, 17-May-1994.) |
| ⊢ (𝐴 ⊆ 𝐵 ↔ (𝐵 ∩ 𝐴) = 𝐴) | ||
| Theorem | nfin 4178 | Bound-variable hypothesis builder for the intersection of classes. (Contributed by NM, 15-Sep-2003.) (Revised by Mario Carneiro, 14-Oct-2016.) Avoid ax-10 2147, ax-11 2163, ax-12 2185. (Revised by SN, 14-May-2025.) |
| ⊢ Ⅎ𝑥𝐴 & ⊢ Ⅎ𝑥𝐵 ⇒ ⊢ Ⅎ𝑥(𝐴 ∩ 𝐵) | ||
| Theorem | nfinOLD 4179 | Obsolete version of nfin 4178 as of 14-May-2025. (Contributed by NM, 15-Sep-2003.) (Revised by Mario Carneiro, 14-Oct-2016.) (Proof modification is discouraged.) (New usage is discouraged.) |
| ⊢ Ⅎ𝑥𝐴 & ⊢ Ⅎ𝑥𝐵 ⇒ ⊢ Ⅎ𝑥(𝐴 ∩ 𝐵) | ||
| Theorem | rabbi2dva 4180* | Deduction from a wff to a restricted class abstraction. (Contributed by NM, 14-Jan-2014.) |
| ⊢ ((𝜑 ∧ 𝑥 ∈ 𝐴) → (𝑥 ∈ 𝐵 ↔ 𝜓)) ⇒ ⊢ (𝜑 → (𝐴 ∩ 𝐵) = {𝑥 ∈ 𝐴 ∣ 𝜓}) | ||
| Theorem | inidm 4181 | Idempotent law for intersection of classes. Theorem 15 of [Suppes] p. 26. (Contributed by NM, 5-Aug-1993.) |
| ⊢ (𝐴 ∩ 𝐴) = 𝐴 | ||
| Theorem | inass 4182 | Associative law for intersection of classes. Exercise 9 of [TakeutiZaring] p. 17. (Contributed by NM, 3-May-1994.) |
| ⊢ ((𝐴 ∩ 𝐵) ∩ 𝐶) = (𝐴 ∩ (𝐵 ∩ 𝐶)) | ||
| Theorem | in12 4183 | A rearrangement of intersection. (Contributed by NM, 21-Apr-2001.) |
| ⊢ (𝐴 ∩ (𝐵 ∩ 𝐶)) = (𝐵 ∩ (𝐴 ∩ 𝐶)) | ||
| Theorem | in32 4184 | A rearrangement of intersection. (Contributed by NM, 21-Apr-2001.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
| ⊢ ((𝐴 ∩ 𝐵) ∩ 𝐶) = ((𝐴 ∩ 𝐶) ∩ 𝐵) | ||
| Theorem | in13 4185 | A rearrangement of intersection. (Contributed by NM, 27-Aug-2012.) |
| ⊢ (𝐴 ∩ (𝐵 ∩ 𝐶)) = (𝐶 ∩ (𝐵 ∩ 𝐴)) | ||
| Theorem | in31 4186 | A rearrangement of intersection. (Contributed by NM, 27-Aug-2012.) |
| ⊢ ((𝐴 ∩ 𝐵) ∩ 𝐶) = ((𝐶 ∩ 𝐵) ∩ 𝐴) | ||
| Theorem | inrot 4187 | Rotate the intersection of 3 classes. (Contributed by NM, 27-Aug-2012.) |
| ⊢ ((𝐴 ∩ 𝐵) ∩ 𝐶) = ((𝐶 ∩ 𝐴) ∩ 𝐵) | ||
| Theorem | in4 4188 | Rearrangement of intersection of 4 classes. (Contributed by NM, 21-Apr-2001.) |
| ⊢ ((𝐴 ∩ 𝐵) ∩ (𝐶 ∩ 𝐷)) = ((𝐴 ∩ 𝐶) ∩ (𝐵 ∩ 𝐷)) | ||
| Theorem | inindi 4189 | Intersection distributes over itself. (Contributed by NM, 6-May-1994.) |
| ⊢ (𝐴 ∩ (𝐵 ∩ 𝐶)) = ((𝐴 ∩ 𝐵) ∩ (𝐴 ∩ 𝐶)) | ||
| Theorem | inindir 4190 | Intersection distributes over itself. (Contributed by NM, 17-Aug-2004.) |
| ⊢ ((𝐴 ∩ 𝐵) ∩ 𝐶) = ((𝐴 ∩ 𝐶) ∩ (𝐵 ∩ 𝐶)) | ||
| Theorem | inss1 4191 | The intersection of two classes is a subset of one of them. Part of Exercise 12 of [TakeutiZaring] p. 18. (Contributed by NM, 27-Apr-1994.) |
| ⊢ (𝐴 ∩ 𝐵) ⊆ 𝐴 | ||
| Theorem | inss2 4192 | The intersection of two classes is a subset of one of them. Part of Exercise 12 of [TakeutiZaring] p. 18. (Contributed by NM, 27-Apr-1994.) |
| ⊢ (𝐴 ∩ 𝐵) ⊆ 𝐵 | ||
| Theorem | ssin 4193 | Subclass of intersection. Theorem 2.8(vii) of [Monk1] p. 26. (Contributed by NM, 15-Jun-2004.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
| ⊢ ((𝐴 ⊆ 𝐵 ∧ 𝐴 ⊆ 𝐶) ↔ 𝐴 ⊆ (𝐵 ∩ 𝐶)) | ||
| Theorem | ssini 4194 | An inference showing that a subclass of two classes is a subclass of their intersection. (Contributed by NM, 24-Nov-2003.) |
| ⊢ 𝐴 ⊆ 𝐵 & ⊢ 𝐴 ⊆ 𝐶 ⇒ ⊢ 𝐴 ⊆ (𝐵 ∩ 𝐶) | ||
| Theorem | ssind 4195 | A deduction showing that a subclass of two classes is a subclass of their intersection. (Contributed by Jonathan Ben-Naim, 3-Jun-2011.) |
| ⊢ (𝜑 → 𝐴 ⊆ 𝐵) & ⊢ (𝜑 → 𝐴 ⊆ 𝐶) ⇒ ⊢ (𝜑 → 𝐴 ⊆ (𝐵 ∩ 𝐶)) | ||
| Theorem | ssrin 4196 | Add right intersection to subclass relation. (Contributed by NM, 16-Aug-1994.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
| ⊢ (𝐴 ⊆ 𝐵 → (𝐴 ∩ 𝐶) ⊆ (𝐵 ∩ 𝐶)) | ||
| Theorem | sslin 4197 | Add left intersection to subclass relation. (Contributed by NM, 19-Oct-1999.) |
| ⊢ (𝐴 ⊆ 𝐵 → (𝐶 ∩ 𝐴) ⊆ (𝐶 ∩ 𝐵)) | ||
| Theorem | ssrind 4198 | Add right intersection to subclass relation. (Contributed by Glauco Siliprandi, 2-Jan-2022.) |
| ⊢ (𝜑 → 𝐴 ⊆ 𝐵) ⇒ ⊢ (𝜑 → (𝐴 ∩ 𝐶) ⊆ (𝐵 ∩ 𝐶)) | ||
| Theorem | ss2in 4199 | Intersection of subclasses. (Contributed by NM, 5-May-2000.) |
| ⊢ ((𝐴 ⊆ 𝐵 ∧ 𝐶 ⊆ 𝐷) → (𝐴 ∩ 𝐶) ⊆ (𝐵 ∩ 𝐷)) | ||
| Theorem | ssinss1 4200 | Intersection preserves subclass relationship. (Contributed by NM, 14-Sep-1999.) |
| ⊢ (𝐴 ⊆ 𝐶 → (𝐴 ∩ 𝐵) ⊆ 𝐶) | ||
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