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Theorem exists1 2691
Description: Two ways to express "exactly one thing exists". The left-hand side requires only one variable to express this. Both sides are false in set theory, see Theorem dtru 5423. (Contributed by NM, 5-Apr-2004.) (Proof shortened by BJ, 7-Oct-2022.)
Assertion
Ref Expression
exists1 (∃!𝑥 𝑥 = 𝑥 ↔ ∀𝑥 𝑥 = 𝑦)
Distinct variable group:   𝑥,𝑦

Proof of Theorem exists1
StepHypRef Expression
1 equid 2045 . . . 4 𝑥 = 𝑥
21bitru 1579 . . 3 (𝑥 = 𝑥 ↔ ⊤)
32eubii 2616 . 2 (∃!𝑥 𝑥 = 𝑥 ↔ ∃!𝑥⊤)
4 euae 2690 . 2 (∃!𝑥⊤ ↔ ∀𝑥 𝑥 = 𝑦)
53, 4bitri 278 1 (∃!𝑥 𝑥 = 𝑥 ↔ ∀𝑥 𝑥 = 𝑦)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wb 209  wal 1568  wtru 1571  ∃!weu 2599
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041
This proof depends on definitions:  df-bi 210  df-an 402  df-tru 1573  df-ex 1813  df-mo 2570  df-eu 2600
This theorem is used by:  exists2  2692
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