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Theorem nelb 3241
Description: A definition of ¬ 𝐴 ∈ 𝐵. (Contributed by Thierry Arnoux, 20-Nov-2023.) (Proof shortened by SN, 23-Jan-2024.) (Proof shortened by Wolf Lammen, 3-Nov-2024.)
Assertion
Ref Expression
nelb (¬ 𝐴 ∈ 𝐵 ↔ ∀𝑥 ∈ 𝐵 𝑥 ≠ 𝐴)
Distinct variable groups:   𝑥,𝐴   𝑥,𝐵

Proof of Theorem nelb
StepHypRef Expression
1 df-ne 2959 . . . 4 (𝑥 ≠ 𝐴 ↔ ¬ 𝑥 = 𝐴)
21ralbii 3111 . . 3 (∀𝑥 ∈ 𝐵 𝑥 ≠ 𝐴 ↔ ∀𝑥 ∈ 𝐵 ¬ 𝑥 = 𝐴)
3 ralnex 3091 . . 3 (∀𝑥 ∈ 𝐵 ¬ 𝑥 = 𝐴 ↔ ¬ ∃𝑥 ∈ 𝐵 𝑥 = 𝐴)
42, 3bitr2i 279 . 2 (¬ ∃𝑥 ∈ 𝐵 𝑥 = 𝐴 ↔ ∀𝑥 ∈ 𝐵 𝑥 ≠ 𝐴)
5 risset 3240 . 2 (𝐴 ∈ 𝐵 ↔ ∃𝑥 ∈ 𝐵 𝑥 = 𝐴)
64, 5xchnxbir 336 1 (¬ 𝐴 ∈ 𝐵 ↔ ∀𝑥 ∈ 𝐵 𝑥 ≠ 𝐴)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  ¬ wn 3   ↔ wb 209   = wceq 1569   ∈ wcel 2146   ≠ wne 2958  ∀wral 3079  ∃wrex 3089
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1944  ax-6 2001  ax-7 2042  ax-8 2148
This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1812  df-clel 2838  df-ne 2959  df-ral 3080  df-rex 3090
This theorem is used by:  dfdif3  4057  inpr0  33182
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