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Theorem xpsnopab 47882
Description: A Cartesian product with a singleton expressed as ordered-pair class abstraction. (Contributed by AV, 27-Jan-2020.)
Assertion
Ref Expression
xpsnopab ({𝑋} × 𝐶) = {⟨𝑎, 𝑏⟩ ∣ (𝑎 = 𝑋𝑏𝐶)}
Distinct variable groups:   𝐶,𝑎,𝑏   𝑋,𝑎,𝑏

Proof of Theorem xpsnopab
StepHypRef Expression
1 df-xp 5706 . 2 ({𝑋} × 𝐶) = {⟨𝑎, 𝑏⟩ ∣ (𝑎 ∈ {𝑋} ∧ 𝑏𝐶)}
2 velsn 4664 . . . 4 (𝑎 ∈ {𝑋} ↔ 𝑎 = 𝑋)
32anbi1i 623 . . 3 ((𝑎 ∈ {𝑋} ∧ 𝑏𝐶) ↔ (𝑎 = 𝑋𝑏𝐶))
43opabbii 5233 . 2 {⟨𝑎, 𝑏⟩ ∣ (𝑎 ∈ {𝑋} ∧ 𝑏𝐶)} = {⟨𝑎, 𝑏⟩ ∣ (𝑎 = 𝑋𝑏𝐶)}
51, 4eqtri 2768 1 ({𝑋} × 𝐶) = {⟨𝑎, 𝑏⟩ ∣ (𝑎 = 𝑋𝑏𝐶)}
Colors of variables: wff setvar class
Syntax hints:  wa 395   = wceq 1537  wcel 2108  {csn 4648  {copab 5228   × cxp 5698
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1793  ax-4 1807  ax-5 1909  ax-6 1967  ax-7 2007  ax-8 2110  ax-9 2118  ax-ext 2711
This theorem depends on definitions:  df-bi 207  df-an 396  df-tru 1540  df-ex 1778  df-sb 2065  df-clab 2718  df-cleq 2732  df-clel 2819  df-v 3490  df-sn 4649  df-opab 5229  df-xp 5706
This theorem is referenced by:  xpiun  47883
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