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Theorem xpsnopab 48955
Description: A Cartesian product with a singleton expressed as ordered-pair class abstraction. (Contributed by AV, 27-Jan-2020.)
Assertion
Ref Expression
xpsnopab ({𝑋} × 𝐶) = {⟨𝑎, 𝑏⟩ ∣ (𝑎 = 𝑋𝑏𝐶)}
Distinct variable groups:   𝐶,𝑎,𝑏   𝑋,𝑎,𝑏

Proof of Theorem xpsnopab
StepHypRef Expression
1 df-xp 5669 . 2 ({𝑋} × 𝐶) = {⟨𝑎, 𝑏⟩ ∣ (𝑎 ∈ {𝑋} ∧ 𝑏𝐶)}
2 velsn 4607 . . . 4 (𝑎 ∈ {𝑋} ↔ 𝑎 = 𝑋)
32anbi1i 636 . . 3 ((𝑎 ∈ {𝑋} ∧ 𝑏𝐶) ↔ (𝑎 = 𝑋𝑏𝐶))
43opabbii 5180 . 2 {⟨𝑎, 𝑏⟩ ∣ (𝑎 ∈ {𝑋} ∧ 𝑏𝐶)} = {⟨𝑎, 𝑏⟩ ∣ (𝑎 = 𝑋𝑏𝐶)}
51, 4eqtri 2788 1 ({𝑋} × 𝐶) = {⟨𝑎, 𝑏⟩ ∣ (𝑎 = 𝑋𝑏𝐶)}
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wa 401   = wceq 1570  wcel 2146  {csn 4591  {copab 5175   × cxp 5661
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2148  ax-9 2156  ax-ext 2737
This proof depends on definitions:  df-bi 210  df-an 402  df-tru 1573  df-ex 1813  df-sb 2100  df-clab 2744  df-cleq 2757  df-clel 2840  df-v 3459  df-sn 4592  df-opab 5176  df-xp 5669
This theorem is used by:  xpiun  48956
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