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Theorem 2reu5lem2 3043
Description: Lemma for 2reu5 3045. (Contributed by Alexander van der Vekens, 17-Jun-2017.)
Assertion
Ref Expression
2reu5lem2 ⊢ (∀x ∈ A ∃*y ∈ B φ ↔ ∀x∃*y(x ∈ A ∧ y ∈ B ∧ φ))
Distinct variable groups:   y,A   x,B   x,y
Allowed substitution hints:   φ(x, y)   A(x)   B(y)

Proof of Theorem 2reu5lem2
StepHypRef Expression
1 df-rmo 2623 . . 3 ⊢ (∃*y ∈ B φ ↔ ∃*y(y ∈ B ∧ φ))
21ralbii 2639 . 2 ⊢ (∀x ∈ A ∃*y ∈ B φ ↔ ∀x ∈ A ∃*y(y ∈ B ∧ φ))
3 df-ral 2620 . . 3 ⊢ (∀x ∈ A ∃*y(y ∈ B ∧ φ) ↔ ∀x(x ∈ A → ∃*y(y ∈ B ∧ φ)))
4 moanimv 2262 . . . . . 6 ⊢ (∃*y(x ∈ A ∧ (y ∈ B ∧ φ)) ↔ (x ∈ A → ∃*y(y ∈ B ∧ φ)))
54bicomi 193 . . . . 5 ⊢ ((x ∈ A → ∃*y(y ∈ B ∧ φ)) ↔ ∃*y(x ∈ A ∧ (y ∈ B ∧ φ)))
6 3anass 938 . . . . . . 7 ⊢ ((x ∈ A ∧ y ∈ B ∧ φ) ↔ (x ∈ A ∧ (y ∈ B ∧ φ)))
76bicomi 193 . . . . . 6 ⊢ ((x ∈ A ∧ (y ∈ B ∧ φ)) ↔ (x ∈ A ∧ y ∈ B ∧ φ))
87mobii 2240 . . . . 5 ⊢ (∃*y(x ∈ A ∧ (y ∈ B ∧ φ)) ↔ ∃*y(x ∈ A ∧ y ∈ B ∧ φ))
95, 8bitri 240 . . . 4 ⊢ ((x ∈ A → ∃*y(y ∈ B ∧ φ)) ↔ ∃*y(x ∈ A ∧ y ∈ B ∧ φ))
109albii 1566 . . 3 ⊢ (∀x(x ∈ A → ∃*y(y ∈ B ∧ φ)) ↔ ∀x∃*y(x ∈ A ∧ y ∈ B ∧ φ))
113, 10bitri 240 . 2 ⊢ (∀x ∈ A ∃*y(y ∈ B ∧ φ) ↔ ∀x∃*y(x ∈ A ∧ y ∈ B ∧ φ))
122, 11bitri 240 1 ⊢ (∀x ∈ A ∃*y ∈ B φ ↔ ∀x∃*y(x ∈ A ∧ y ∈ B ∧ φ))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 176   ∧ wa 358   ∧ w3a 934  ∀wal 1540   ∈ wcel 1710  ∃*wmo 2205  ∀wral 2615  ∃*wrmo 2618
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-6 1729  ax-7 1734  ax-11 1746  ax-12 1925
This proof depends on definitions:  df-bi 177  df-or 359  df-an 360  df-3an 936  df-tru 1319  df-ex 1542  df-nf 1545  df-sb 1649  df-eu 2208  df-mo 2209  df-ral 2620  df-rmo 2623
This theorem is used by:  2reu5lem3  3044
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