Theorem hbs1 1909

Description: x is not free in [ y / x ] ph when x and y are distinct. (Contributed by NM, 5-Aug-1993.) (Proof by Jim Kingdon, 16-Dec-2017.) (New usage is discouraged.)

Assertion

Ref	Expression
hbs1	|- ( [ y / x ] ph -> A. x [ y / x ] ph )

Distinct variable group:   x, y

Allowed substitution hints:   ph( x, y)

Proof of Theorem hbs1

Step	Hyp	Ref	Expression
1		sb6 1858	. 2 |- ( [ y / x ] ph <-> A. x ( x = y -> ph ) )
2		ax-ial 1514	. 2 |- ( A. x ( x = y -> ph ) -> A. x A. x ( x = y -> ph ) )
3	1, 2	hbxfrbi 1448	1 |- ( [ y / x ] ph -> A. x [ y / x ] ph )

Syntax hints:   -> wi 4   A.wal 1329   [wsb 1735

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1423  ax-gen 1425  ax-ie1 1469  ax-ie2 1470  ax-8 1482  ax-11 1484  ax-4 1487  ax-17 1506  ax-i9 1510  ax-ial 1514

This theorem depends on definitions:  df-bi 116  df-sb 1736

This theorem is referenced by:  nfs1v  1910  sb9v  1951  eu1  2022  mopick  2075  hbab1  2126