Theorem sbceq1g 3100

Description: Move proper substitution to first argument of an equality. (Contributed by NM, 30-Nov-2005.)

Assertion

Ref	Expression
sbceq1g	|- ( A e. V -> ( [. A / x ]. B = C <-> [_ A / x ]_ B = C ) )

Distinct variable group:   x, C

Allowed substitution hints:   A( x)   B( x)   V( x)

Proof of Theorem sbceq1g

Step	Hyp	Ref	Expression
1		sbceqg 3096	. 2 |- ( A e. V -> ( [. A / x ]. B = C <-> [_ A / x ]_ B = [_ A / x ]_ C ) )
2		csbconstg 3094	. . 3 |- ( A e. V -> [_ A / x ]_ C = C )
3	2	eqeq2d 2205	. 2 |- ( A e. V -> ( [_ A / x ]_ B = [_ A / x ]_ C <-> [_ A / x ]_ B = C ) )
4	1, 3	bitrd 188	1 |- ( A e. V -> ( [. A / x ]. B = C <-> [_ A / x ]_ B = C ) )

Syntax hints:   -> wi 4   <-> wb 105   = wceq 1364   e. wcel 2164   [.wsbc 2985   [_csb 3080

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 710  ax-5 1458  ax-7 1459  ax-gen 1460  ax-ie1 1504  ax-ie2 1505  ax-8 1515  ax-10 1516  ax-11 1517  ax-i12 1518  ax-bndl 1520  ax-4 1521  ax-17 1537  ax-i9 1541  ax-ial 1545  ax-i5r 1546  ax-ext 2175

This theorem depends on definitions:  df-bi 117  df-tru 1367  df-nf 1472  df-sb 1774  df-clab 2180  df-cleq 2186  df-clel 2189  df-nfc 2325  df-v 2762  df-sbc 2986  df-csb 3081

This theorem is referenced by:  f1od2  6288