Theorem eleq2w 2150

Description: Weaker version of eleq2 2152 (but more general than elequ2 1649) not depending on ax-ext 2071 nor df-cleq 2082. (Contributed by BJ, 29-Sep-2019.)

Assertion

Ref	Expression
eleq2w	⊢ (𝑥 = 𝑦 → (𝐴 ∈ 𝑥 ↔ 𝐴 ∈ 𝑦))

Proof of Theorem eleq2w

Dummy variable 𝑧 is distinct from all other variables.

Step	Hyp	Ref	Expression
1		elequ2 1649	. . . 4 ⊢ (𝑥 = 𝑦 → (𝑧 ∈ 𝑥 ↔ 𝑧 ∈ 𝑦))
2	1	anbi2d 453	. . 3 ⊢ (𝑥 = 𝑦 → ((𝑧 = 𝐴 ∧ 𝑧 ∈ 𝑥) ↔ (𝑧 = 𝐴 ∧ 𝑧 ∈ 𝑦)))
3	2	exbidv 1754	. 2 ⊢ (𝑥 = 𝑦 → (∃𝑧(𝑧 = 𝐴 ∧ 𝑧 ∈ 𝑥) ↔ ∃𝑧(𝑧 = 𝐴 ∧ 𝑧 ∈ 𝑦)))
4		df-clel 2085	. 2 ⊢ (𝐴 ∈ 𝑥 ↔ ∃𝑧(𝑧 = 𝐴 ∧ 𝑧 ∈ 𝑥))
5		df-clel 2085	. 2 ⊢ (𝐴 ∈ 𝑦 ↔ ∃𝑧(𝑧 = 𝐴 ∧ 𝑧 ∈ 𝑦))
6	3, 4, 5	3bitr4g 222	1 ⊢ (𝑥 = 𝑦 → (𝐴 ∈ 𝑥 ↔ 𝐴 ∈ 𝑦))

Syntax hints:   → wi 4   ∧ wa 103   ↔ wb 104   = wceq 1290  ∃wex 1427   ∈ wcel 1439

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1382  ax-gen 1384  ax-ie1 1428  ax-ie2 1429  ax-8 1441  ax-4 1446  ax-14 1451  ax-17 1465  ax-i9 1469  ax-ial 1473

This theorem depends on definitions:  df-bi 116  df-clel 2085

This theorem is referenced by: (None)