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| Mirrors > Home > ILE Home > Th. List > sbimv | GIF version | ||
| Description: Intuitionistic proof of sbim 2013 where 𝑥 and 𝑦 are distinct. (Contributed by Jim Kingdon, 18-Jan-2018.) |
| Ref | Expression |
|---|---|
| sbimv | ⊢ ([𝑦 / 𝑥](𝜑 → 𝜓) ↔ ([𝑦 / 𝑥]𝜑 → [𝑦 / 𝑥]𝜓)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | sbi1v 1946 | . 2 ⊢ ([𝑦 / 𝑥](𝜑 → 𝜓) → ([𝑦 / 𝑥]𝜑 → [𝑦 / 𝑥]𝜓)) | |
| 2 | sbi2v 1947 | . 2 ⊢ (([𝑦 / 𝑥]𝜑 → [𝑦 / 𝑥]𝜓) → [𝑦 / 𝑥](𝜑 → 𝜓)) | |
| 3 | 1, 2 | impbii 126 | 1 ⊢ ([𝑦 / 𝑥](𝜑 → 𝜓) ↔ ([𝑦 / 𝑥]𝜑 → [𝑦 / 𝑥]𝜓)) |
| Colors of variables: wff set class |
| Syntax hints: → wi 4 ↔ wb 105 [wsb 1815 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-5 1500 ax-gen 1502 ax-ie1 1546 ax-ie2 1547 ax-8 1557 ax-11 1559 ax-4 1563 ax-17 1579 ax-i9 1583 ax-ial 1587 ax-i5r 1588 |
| This theorem depends on definitions: df-bi 117 df-sb 1816 |
| This theorem is referenced by: sblimv 1950 sbim 2013 |
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