Theorem 3anrev 1100

Description: Reversal law for triple conjunction. (Contributed by NM, 21-Apr-1994.)

Assertion

Ref	Expression
3anrev	⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) ↔ (𝜒 ∧ 𝜓 ∧ 𝜑))

Proof of Theorem 3anrev

Step	Hyp	Ref	Expression
1		3ancoma 1097	. 2 ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) ↔ (𝜓 ∧ 𝜑 ∧ 𝜒))
2		3anrot 1099	. 2 ⊢ ((𝜒 ∧ 𝜓 ∧ 𝜑) ↔ (𝜓 ∧ 𝜑 ∧ 𝜒))
3	1, 2	bitr4i 278	1 ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) ↔ (𝜒 ∧ 𝜓 ∧ 𝜑))

Syntax hints:   ↔ wb 206   ∧ w3a 1086

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 207  df-an 396  df-3an 1088

This theorem is referenced by:  an33rean  1485  nnmcan  8560  odupos  18247  wwlks2onsym  29982  frgr3v  30299  bnj345  34819  bnj1098  34888  pocnv  35906  btwnswapid2  36161  colinbtwnle  36261  uunT11p2  44980  uunT12p5  44986  uun2221p2  44997  grtriproplem  48127  grtrif1o  48130