Theorem dfnul4OLD 4329

Description: Obsolete version of dfnul4 4324 as of 23-Sep-2024. (Contributed by BJ, 30-Nov-2019.) (Proof modification is discouraged.) (New usage is discouraged.)

Assertion

Ref	Expression
dfnul4OLD	⊢ ∅ = {𝑥 ∣ ⊥}

Proof of Theorem dfnul4OLD

Step	Hyp	Ref	Expression
1		dfnul2 4325	. 2 ⊢ ∅ = {𝑥 ∣ ¬ 𝑥 = 𝑥}
2		equid 2014	. . . . 5 ⊢ 𝑥 = 𝑥
3	2	notnoti 143	. . . 4 ⊢ ¬ ¬ 𝑥 = 𝑥
4	3	bifal 1556	. . 3 ⊢ (¬ 𝑥 = 𝑥 ↔ ⊥)
5	4	abbii 2801	. 2 ⊢ {𝑥 ∣ ¬ 𝑥 = 𝑥} = {𝑥 ∣ ⊥}
6	1, 5	eqtri 2759	1 ⊢ ∅ = {𝑥 ∣ ⊥}

Syntax hints:  ¬ wn 3   = wceq 1540  ⊥wfal 1552  {cab 2708  ∅c0 4322

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1912  ax-6 1970  ax-7 2010  ax-9 2115  ax-ext 2702

This theorem depends on definitions:  df-bi 206  df-an 396  df-tru 1543  df-fal 1553  df-ex 1781  df-sb 2067  df-clab 2709  df-cleq 2723  df-dif 3951  df-nul 4323

This theorem is referenced by: (None)