MPE Home Metamath Proof Explorer < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  MPE Home  >  Th. List  >  bifal Structured version   Visualization version   GIF version

Theorem bifal 1552
Description: A contradiction is equivalent to falsehood. (Contributed by Mario Carneiro, 9-May-2015.)
Hypothesis
Ref Expression
bifal.1 ¬ 𝜑
Assertion
Ref Expression
bifal (𝜑 ↔ ⊥)

Proof of Theorem bifal
StepHypRef Expression
1 bifal.1 . 2 ¬ 𝜑
2 fal 1550 . 2 ¬ ⊥
31, 22false 378 1 (𝜑 ↔ ⊥)
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wb 208  wfal 1548
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This theorem depends on definitions:  df-bi 209  df-tru 1539  df-fal 1549
This theorem is referenced by:  falantru  1571  trunortruOLD  1586  trunorfalOLD  1588  ralnralall  4461  tgcgr4  26320  frgrregord013  28177  nrmo  33762  bj-df-nul  34352  bicontr  35362  aibnbaif  43150  aifftbifffaibif  43164  atnaiana  43166
  Copyright terms: Public domain W3C validator