Theorem bifal 1558

Description: A contradiction is equivalent to falsehood. (Contributed by Mario Carneiro, 9-May-2015.)

Hypothesis

Ref	Expression
bifal.1	⊢ ¬ 𝜑

Assertion

Ref	Expression
bifal	⊢ (𝜑 ↔ ⊥)

Proof of Theorem bifal

Step	Hyp	Ref	Expression
1		bifal.1	. 2 ⊢ ¬ 𝜑
2		fal 1556	. 2 ⊢ ¬ ⊥
3	1, 2	2false 375	1 ⊢ (𝜑 ↔ ⊥)

Syntax hints:  ¬ wn 3   ↔ wb 206  ⊥wfal 1554

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 207  df-tru 1545  df-fal 1555

This theorem is referenced by:  falantru  1577  dfnul4  4276  dfnul2  4277  abf  4347  ralnralall  4454  tgcgr4  28616  frgrregord013  30483  nrmo  36611  bj-ntrufal  36853  bicontr  38418  aibnbaif  47370  aifftbifffaibif  47384  atnaiana  47386