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Theorem dfnul4 4263
Description: Alternate definition of the empty class/set. (Contributed by BJ, 30-Nov-2019.) Avoid ax-8 2121, df-clel 2814. (Revised by GG, 3-Sep-2024.) Prove directly from definition to allow shortening dfnul2 4264. (Revised by BJ, 23-Sep-2024.)
Assertion
Ref Expression
dfnul4 ∅ = {𝑥 ∣ ⊥}

Proof of Theorem dfnul4
StepHypRef Expression
1 df-nul 4262 . 2 ∅ = (V ∖ V)
2 df-dif 3886 . 2 (V ∖ V) = {𝑥 ∣ (𝑥 ∈ V ∧ ¬ 𝑥 ∈ V)}
3 pm3.24 403 . . . 4 ¬ (𝑥 ∈ V ∧ ¬ 𝑥 ∈ V)
43bifal 1563 . . 3 ((𝑥 ∈ V ∧ ¬ 𝑥 ∈ V) ↔ ⊥)
54abbii 2806 . 2 {𝑥 ∣ (𝑥 ∈ V ∧ ¬ 𝑥 ∈ V)} = {𝑥 ∣ ⊥}
61, 2, 53eqtri 2766 1 ∅ = {𝑥 ∣ ⊥}
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wa 396   = wceq 1547  wfal 1559  wcel 2119  {cab 2717  Vcvv 3431  cdif 3880  c0 4261
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1802  ax-4 1816  ax-5 1917  ax-6 1974  ax-7 2015  ax-9 2129  ax-ext 2711
This theorem depends on definitions:  df-bi 208  df-an 397  df-tru 1550  df-fal 1560  df-ex 1787  df-sb 2074  df-clab 2718  df-cleq 2731  df-dif 3886  df-nul 4262
This theorem is referenced by:  dfnul2  4264  dfnul3  4265  noel  4266  vn0  4273  eq0  4278  ab0w  4307  ab0  4308  abf  4334  csbprc  4337  bj-dfnul2  36881
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