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Theorem dfnul4 4288
Description: Alternate definition of the empty class/set. (Contributed by BJ, 30-Nov-2019.) Avoid ax-8 2145, df-clel 2838. (Revised by GG, 3-Sep-2024.) Prove directly from definition to allow shortening dfnul2 4289. (Revised by BJ, 23-Sep-2024.)
Assertion
Ref Expression
dfnul4 ∅ = {𝑥 ∣ ⊥}

Proof of Theorem dfnul4
StepHypRef Expression
1 df-nul 4287 . 2 ∅ = (V ∖ V)
2 df-dif 3908 . 2 (V ∖ V) = {𝑥 ∣ (𝑥 ∈ V ∧ ¬ 𝑥 ∈ V)}
3 pm3.24 407 . . . 4 ¬ (𝑥 ∈ V ∧ ¬ 𝑥 ∈ V)
43bifal 1586 . . 3 ((𝑥 ∈ V ∧ ¬ 𝑥 ∈ V) ↔ ⊥)
54abbii 2830 . 2 {𝑥 ∣ (𝑥 ∈ V ∧ ¬ 𝑥 ∈ V)} = {𝑥 ∣ ⊥}
61, 2, 53eqtri 2790 1 ∅ = {𝑥 ∣ ⊥}
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wa 400   = wceq 1570  wfal 1582  wcel 2143  {cab 2741  Vcvv 3455  cdif 3902  c0 4286
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1825  ax-4 1839  ax-5 1940  ax-6 1997  ax-7 2038  ax-9 2153  ax-ext 2735
This theorem depends on definitions:  df-bi 210  df-an 401  df-tru 1573  df-fal 1583  df-ex 1810  df-sb 2097  df-clab 2742  df-cleq 2755  df-dif 3908  df-nul 4287
This theorem is referenced by:  dfnul2  4289  dfnul3  4290  noel  4291  vn0  4298  vn0OLD  4299  eq0  4304  ab0w  4335  ab0  4336  abf  4371  csbprc  4374  bj-dfnul2  37183  bj-vn0ALT  37728
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