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Theorem flddivrng 38373
Description: A field is a division ring. (Contributed by Jeff Madsen, 10-Jun-2010.) (Revised by Mario Carneiro, 15-Dec-2013.) (New usage is discouraged.)
Assertion
Ref Expression
flddivrng (𝐾 ∈ Fld → 𝐾 ∈ DivRingOps)

Proof of Theorem flddivrng
StepHypRef Expression
1 df-fld 38366 . . 3 Fld = (DivRingOps ∩ Com2)
2 inss1 4172 . . 3 (DivRingOps ∩ Com2) ⊆ DivRingOps
31, 2eqsstri 3968 . 2 Fld ⊆ DivRingOps
43sseli 3918 1 (𝐾 ∈ Fld → 𝐾 ∈ DivRingOps)
Colors of variables: wff setvar class
Syntax hints:  wi 4  wcel 2119  cin 3889  DivRingOpscdrng 38322  Com2ccm2 38363  Fldcfld 38365
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1802  ax-4 1816  ax-5 1917  ax-6 1974  ax-7 2015  ax-8 2121  ax-9 2129  ax-ext 2712
This theorem depends on definitions:  df-bi 208  df-an 397  df-tru 1550  df-ex 1787  df-sb 2074  df-clab 2719  df-cleq 2732  df-clel 2815  df-v 3434  df-in 3897  df-ss 3907  df-fld 38366
This theorem is referenced by:  isfld2  38379  isfldidl  38442
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