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Theorem flddivrng 38196
Description: A field is a division ring. (Contributed by Jeff Madsen, 10-Jun-2010.) (Revised by Mario Carneiro, 15-Dec-2013.) (New usage is discouraged.)
Assertion
Ref Expression
flddivrng (𝐾 ∈ Fld → 𝐾 ∈ DivRingOps)

Proof of Theorem flddivrng
StepHypRef Expression
1 df-fld 38189 . . 3 Fld = (DivRingOps ∩ Com2)
2 inss1 4189 . . 3 (DivRingOps ∩ Com2) ⊆ DivRingOps
31, 2eqsstri 3980 . 2 Fld ⊆ DivRingOps
43sseli 3929 1 (𝐾 ∈ Fld → 𝐾 ∈ DivRingOps)
Colors of variables: wff setvar class
Syntax hints:  wi 4  wcel 2113  cin 3900  DivRingOpscdrng 38145  Com2ccm2 38186  Fldcfld 38188
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1968  ax-7 2009  ax-8 2115  ax-9 2123  ax-ext 2708
This theorem depends on definitions:  df-bi 207  df-an 396  df-tru 1544  df-ex 1781  df-sb 2068  df-clab 2715  df-cleq 2728  df-clel 2811  df-v 3442  df-in 3908  df-ss 3918  df-fld 38189
This theorem is referenced by:  isfld2  38202  isfldidl  38265
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