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Mirrors > Home > MPE Home > Th. List > Mathboxes > flddivrng | Structured version Visualization version GIF version |
Description: A field is a division ring. (Contributed by Jeff Madsen, 10-Jun-2010.) (Revised by Mario Carneiro, 15-Dec-2013.) (New usage is discouraged.) |
Ref | Expression |
---|---|
flddivrng | ⊢ (𝐾 ∈ Fld → 𝐾 ∈ DivRingOps) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | df-fld 37952 | . . 3 ⊢ Fld = (DivRingOps ∩ Com2) | |
2 | inss1 4258 | . . 3 ⊢ (DivRingOps ∩ Com2) ⊆ DivRingOps | |
3 | 1, 2 | eqsstri 4043 | . 2 ⊢ Fld ⊆ DivRingOps |
4 | 3 | sseli 4004 | 1 ⊢ (𝐾 ∈ Fld → 𝐾 ∈ DivRingOps) |
Colors of variables: wff setvar class |
Syntax hints: → wi 4 ∈ wcel 2108 ∩ cin 3975 DivRingOpscdrng 37908 Com2ccm2 37949 Fldcfld 37951 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1793 ax-4 1807 ax-5 1909 ax-6 1967 ax-7 2007 ax-8 2110 ax-9 2118 ax-ext 2711 |
This theorem depends on definitions: df-bi 207 df-an 396 df-tru 1540 df-ex 1778 df-sb 2065 df-clab 2718 df-cleq 2732 df-clel 2819 df-v 3490 df-in 3983 df-ss 3993 df-fld 37952 |
This theorem is referenced by: isfld2 37965 isfldidl 38028 |
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