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Theorem flddivrng 36867
Description: A field is a division ring. (Contributed by Jeff Madsen, 10-Jun-2010.) (Revised by Mario Carneiro, 15-Dec-2013.) (New usage is discouraged.)
Assertion
Ref Expression
flddivrng (𝐾 ∈ Fld → 𝐾 ∈ DivRingOps)

Proof of Theorem flddivrng
StepHypRef Expression
1 df-fld 36860 . . 3 Fld = (DivRingOps ∩ Com2)
2 inss1 4229 . . 3 (DivRingOps ∩ Com2) ⊆ DivRingOps
31, 2eqsstri 4017 . 2 Fld ⊆ DivRingOps
43sseli 3979 1 (𝐾 ∈ Fld → 𝐾 ∈ DivRingOps)
Colors of variables: wff setvar class
Syntax hints:  wi 4  wcel 2107  cin 3948  DivRingOpscdrng 36816  Com2ccm2 36857  Fldcfld 36859
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1798  ax-4 1812  ax-5 1914  ax-6 1972  ax-7 2012  ax-8 2109  ax-9 2117  ax-ext 2704
This theorem depends on definitions:  df-bi 206  df-an 398  df-tru 1545  df-ex 1783  df-sb 2069  df-clab 2711  df-cleq 2725  df-clel 2811  df-v 3477  df-in 3956  df-ss 3966  df-fld 36860
This theorem is referenced by:  isfld2  36873  isfldidl  36936
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