MPE Home Metamath Proof Explorer < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  MPE Home  >  Th. List  >  fndmu Structured version   Visualization version   GIF version

Theorem fndmu 6460
Description: A function has a unique domain. (Contributed by NM, 11-Aug-1994.)
Assertion
Ref Expression
fndmu ((𝐹 Fn 𝐴𝐹 Fn 𝐵) → 𝐴 = 𝐵)

Proof of Theorem fndmu
StepHypRef Expression
1 fndm 6457 . 2 (𝐹 Fn 𝐴 → dom 𝐹 = 𝐴)
2 fndm 6457 . 2 (𝐹 Fn 𝐵 → dom 𝐹 = 𝐵)
31, 2sylan9req 2879 1 ((𝐹 Fn 𝐴𝐹 Fn 𝐵) → 𝐴 = 𝐵)
Colors of variables: wff setvar class
Syntax hints:  wi 4  wa 398   = wceq 1537  dom cdm 5557   Fn wfn 6352
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1970  ax-7 2015  ax-9 2124  ax-ext 2795
This theorem depends on definitions:  df-bi 209  df-an 399  df-ex 1781  df-cleq 2816  df-fn 6360
This theorem is referenced by:  fodmrnu  6600  0fz1  12930  lmodfopnelem1  19672  grporn  28300  hon0  29572  2ffzoeq  43535
  Copyright terms: Public domain W3C validator