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Theorem fndmu 6571
Description: A function has a unique domain. (Contributed by NM, 11-Aug-1994.)
Assertion
Ref Expression
fndmu ((𝐹 Fn 𝐴𝐹 Fn 𝐵) → 𝐴 = 𝐵)

Proof of Theorem fndmu
StepHypRef Expression
1 fndm 6567 . 2 (𝐹 Fn 𝐴 → dom 𝐹 = 𝐴)
2 fndm 6567 . 2 (𝐹 Fn 𝐵 → dom 𝐹 = 𝐵)
31, 2sylan9req 2797 1 ((𝐹 Fn 𝐴𝐹 Fn 𝐵) → 𝐴 = 𝐵)
Colors of variables: wff setvar class
Syntax hints:  wi 4  wa 397   = wceq 1539  dom cdm 5600   Fn wfn 6453
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1911  ax-6 1969  ax-7 2009  ax-9 2114  ax-ext 2707
This theorem depends on definitions:  df-bi 206  df-an 398  df-ex 1780  df-cleq 2728  df-fn 6461
This theorem is referenced by:  fodmrnu  6726  0fz1  13326  lmodfopnelem1  20208  grporn  28932  hon0  30204  2ffzoeq  45064
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