Theorem iineq1i 36803

Description: Equality theorem for indexed intersection. Inference version. (Contributed by GG, 1-Sep-2025.)

Hypothesis

Ref	Expression
iineq1i.1	⊢ 𝐴 = 𝐵

Assertion

Ref	Expression
iineq1i	⊢ ∩ 𝑥 ∈ 𝐴 𝐶 = ∩ 𝑥 ∈ 𝐵 𝐶

Proof of Theorem iineq1i

Dummy variable 𝑡 is distinct from all other variables.

Step	Hyp	Ref	Expression
1		iineq1i.1	. . . . . 6 ⊢ 𝐴 = 𝐵
2	1	eleq2i 2854	. . . . 5 ⊢ (𝑥 ∈ 𝐴 ↔ 𝑥 ∈ 𝐵)
3	2	imbi1i 352	. . . 4 ⊢ ((𝑥 ∈ 𝐴 → 𝑡 ∈ 𝐶) ↔ (𝑥 ∈ 𝐵 → 𝑡 ∈ 𝐶))
4	3	ralbii2 3106	. . 3 ⊢ (∀𝑥 ∈ 𝐴 𝑡 ∈ 𝐶 ↔ ∀𝑥 ∈ 𝐵 𝑡 ∈ 𝐶)
5	4	abbii 2829	. 2 ⊢ {𝑡 ∣ ∀𝑥 ∈ 𝐴 𝑡 ∈ 𝐶} = {𝑡 ∣ ∀𝑥 ∈ 𝐵 𝑡 ∈ 𝐶}
6		df-iin 4957	. 2 ⊢ ∩ 𝑥 ∈ 𝐴 𝐶 = {𝑡 ∣ ∀𝑥 ∈ 𝐴 𝑡 ∈ 𝐶}
7		df-iin 4957	. 2 ⊢ ∩ 𝑥 ∈ 𝐵 𝐶 = {𝑡 ∣ ∀𝑥 ∈ 𝐵 𝑡 ∈ 𝐶}
8	5, 6, 7	3eqtr4i 2795	1 ⊢ ∩ 𝑥 ∈ 𝐴 𝐶 = ∩ 𝑥 ∈ 𝐵 𝐶

This proof depends on syntax axioms:   = wceq 1570   ∈ wcel 2145  {cab 2740  ∀wral 3078  ∩ ciin 4955

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2734

This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1813  df-sb 2100  df-clab 2741  df-cleq 2754  df-clel 2837  df-ral 3079  df-iin 4957

This theorem is used by: (None)