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Theorem trcleq1 14999
Description: Equality of relations implies equality of transitive closures. (Contributed by RP, 9-May-2020.)
Assertion
Ref Expression
trcleq1 (𝑅 = 𝑆 {𝑟 ∣ (𝑅𝑟 ∧ (𝑟𝑟) ⊆ 𝑟)} = {𝑟 ∣ (𝑆𝑟 ∧ (𝑟𝑟) ⊆ 𝑟)})
Distinct variable groups:   𝑅,𝑟   𝑆,𝑟

Proof of Theorem trcleq1
StepHypRef Expression
1 cleq1 14993 1 (𝑅 = 𝑆 {𝑟 ∣ (𝑅𝑟 ∧ (𝑟𝑟) ⊆ 𝑟)} = {𝑟 ∣ (𝑆𝑟 ∧ (𝑟𝑟) ⊆ 𝑟)})
Colors of variables: wff setvar class
Syntax hints:  wi 4  wa 399   = wceq 1559  {cab 2739  wss 3904   cint 4904  ccom 5649
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1814  ax-4 1828  ax-5 1929  ax-6 1986  ax-7 2027  ax-9 2151  ax-ext 2733
This theorem depends on definitions:  df-bi 209  df-an 400  df-ex 1799  df-sb 2090  df-clab 2740  df-cleq 2753  df-ral 3076  df-rex 3086  df-ss 3921  df-int 4905
This theorem is referenced by:  trclfv  15010
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