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Theorem trcleq1 14912
Description: Equality of relations implies equality of transitive closures. (Contributed by RP, 9-May-2020.)
Assertion
Ref Expression
trcleq1 (𝑅 = 𝑆 {𝑟 ∣ (𝑅𝑟 ∧ (𝑟𝑟) ⊆ 𝑟)} = {𝑟 ∣ (𝑆𝑟 ∧ (𝑟𝑟) ⊆ 𝑟)})
Distinct variable groups:   𝑅,𝑟   𝑆,𝑟

Proof of Theorem trcleq1
StepHypRef Expression
1 cleq1 14906 1 (𝑅 = 𝑆 {𝑟 ∣ (𝑅𝑟 ∧ (𝑟𝑟) ⊆ 𝑟)} = {𝑟 ∣ (𝑆𝑟 ∧ (𝑟𝑟) ⊆ 𝑟)})
Colors of variables: wff setvar class
Syntax hints:  wi 4  wa 395   = wceq 1541  {cab 2714  wss 3901   cint 4902  ccom 5628
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1968  ax-7 2009  ax-9 2123  ax-ext 2708
This theorem depends on definitions:  df-bi 207  df-an 396  df-ex 1781  df-sb 2068  df-clab 2715  df-cleq 2728  df-ral 3052  df-rex 3061  df-ss 3918  df-int 4903
This theorem is referenced by:  trclfv  14923
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