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Mirrors > Home > NFE Home > Th. List > eqtr2 | GIF version |
Description: A transitive law for class equality. (Contributed by NM, 20-May-2005.) (Proof shortened by Andrew Salmon, 25-May-2011.) |
Ref | Expression |
---|---|
eqtr2 | ⊢ ((A = B ∧ A = C) → B = C) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | eqcom 2355 | . 2 ⊢ (A = B ↔ B = A) | |
2 | eqtr 2370 | . 2 ⊢ ((B = A ∧ A = C) → B = C) | |
3 | 1, 2 | sylanb 458 | 1 ⊢ ((A = B ∧ A = C) → B = C) |
Colors of variables: wff setvar class |
Syntax hints: → wi 4 ∧ wa 358 = wceq 1642 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1546 ax-5 1557 ax-17 1616 ax-9 1654 ax-8 1675 ax-11 1746 ax-ext 2334 |
This theorem depends on definitions: df-bi 177 df-an 360 df-ex 1542 df-cleq 2346 |
This theorem is referenced by: eqvinc 2967 dfxp2 5114 1stfo 5506 2ndfo 5507 swapf1o 5512 brtxp 5784 enprmaplem3 6079 peano4nc 6151 nchoicelem17 6306 fnfrec 6321 |
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