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Theorem baibd 923
Description: Move conjunction outside of biconditional. (Contributed by Mario Carneiro, 11-Sep-2015.)
Hypothesis
Ref Expression
baibd.1  |-  ( ph  ->  ( ps  <->  ( ch  /\ 
th ) ) )
Assertion
Ref Expression
baibd  |-  ( (
ph  /\  ch )  ->  ( ps  <->  th )
)

Proof of Theorem baibd
StepHypRef Expression
1 baibd.1 . 2  |-  ( ph  ->  ( ps  <->  ( ch  /\ 
th ) ) )
2 ibar 301 . . 3  |-  ( ch 
->  ( th  <->  ( ch  /\ 
th ) ) )
32bicomd 141 . 2  |-  ( ch 
->  ( ( ch  /\  th )  <->  th ) )
41, 3sylan9bb 462 1  |-  ( (
ph  /\  ch )  ->  ( ps  <->  th )
)
Colors of variables: wff set class
Syntax hints:    -> wi 4    /\ wa 104    <-> wb 105
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108
This theorem depends on definitions:  df-bi 117
This theorem is referenced by:  eluz  9543  elicc4  9942  divalgmodcl  11935  eqglact  13089  eqgid  13090  iscrng2  13203  issubrg3  13373  iscld2  13643  cncnp2m  13770  cnnei  13771  reopnap  14077  cnlimc  14180
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