Theorem neeq2d 2355

Description: Deduction for inequality. (Contributed by NM, 25-Oct-1999.)

Hypothesis

Ref	Expression
neeq1d.1	|- ( ph -> A = B )

Assertion

Ref	Expression
neeq2d	|- ( ph -> ( C =/= A <-> C =/= B ) )

Proof of Theorem neeq2d

Step	Hyp	Ref	Expression
1		neeq1d.1	. 2 |- ( ph -> A = B )
2		neeq2 2350	. 2 |- ( A = B -> ( C =/= A <-> C =/= B ) )
3	1, 2	syl 14	1 |- ( ph -> ( C =/= A <-> C =/= B ) )

Syntax hints:   -> wi 4   <-> wb 104   = wceq 1343   =/= wne 2336

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-in1 604  ax-in2 605  ax-5 1435  ax-gen 1437  ax-4 1498  ax-17 1514  ax-ext 2147

This theorem depends on definitions:  df-bi 116  df-cleq 2158  df-ne 2337

This theorem is referenced by:  neeq12d  2356  neeqtrd  2364  sqrt2irr  12094  ennnfonelemk  12333  ennnfoneleminc  12344  ennnfonelemex  12347  ennnfonelemnn0  12355  ennnfonelemr  12356