Theorem orim1i 749

Description: Introduce disjunct to both sides of an implication. (Contributed by NM, 6-Jun-1994.)

Hypothesis

Ref	Expression
orim1i.1	⊢ (𝜑 → 𝜓)

Assertion

Ref	Expression
orim1i	⊢ ((𝜑 ∨ 𝜒) → (𝜓 ∨ 𝜒))

Proof of Theorem orim1i

Step	Hyp	Ref	Expression
1		orim1i.1	. 2 ⊢ (𝜑 → 𝜓)
2		id 19	. 2 ⊢ (𝜒 → 𝜒)
3	1, 2	orim12i 748	1 ⊢ ((𝜑 ∨ 𝜒) → (𝜓 ∨ 𝜒))

Syntax hints:   → wi 4   ∨ wo 697

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-io 698

This theorem depends on definitions:  df-bi 116

This theorem is referenced by:  19.34  1662  dveeq2or  1788  sbequilem  1810  sbequi  1811  dvelimALT  1983  dvelimfv  1984  dvelimor  1991  r19.45av  2589  acexmidlemcase  5762  nnm1nn0  9011  triap  13213