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Theorem axpow3 5330
Description: A variant of the Axiom of Power Sets ax-pow 5327. For any set 𝑥, there exists a set 𝑦 whose members are exactly the subsets of 𝑥 i.e. the power set of 𝑥. Axiom Pow of [BellMachover] p. 466. (Contributed by NM, 4-Jun-2006.)
Assertion
Ref Expression
axpow3 ∃𝑦∀𝑧(𝑧 ⊆ 𝑥 ↔ 𝑧 ∈ 𝑦)
Distinct variable group:   𝑥,𝑦,𝑧

Proof of Theorem axpow3
StepHypRef Expression
1 axpow2 5329 . . 3 ∃𝑦∀𝑧(𝑧 ⊆ 𝑥 → 𝑧 ∈ 𝑦)
21sepexi 5256 . 2 ∃𝑦∀𝑧(𝑧 ∈ 𝑦 ↔ 𝑧 ⊆ 𝑥)
3 bicom1 224 . . 3 ((𝑧 ∈ 𝑦 ↔ 𝑧 ⊆ 𝑥) → (𝑧 ⊆ 𝑥 ↔ 𝑧 ∈ 𝑦))
43alimi 1844 . 2 (∀𝑧(𝑧 ∈ 𝑦 ↔ 𝑧 ⊆ 𝑥) → ∀𝑧(𝑧 ⊆ 𝑥 ↔ 𝑧 ∈ 𝑦))
52, 4eximii 1870 1 ∃𝑦∀𝑧(𝑧 ⊆ 𝑥 ↔ 𝑧 ∈ 𝑦)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   ↔ wb 209  ∀wal 1568  ∃wex 1812   ⊆ wss 3899
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-sep 5249  ax-pow 5327
This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1813  df-ss 3916
This theorem is used by: (None)
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