Theorem bj-df-sb 36894

Description: Proposed definition to replace df-sb 2069 and df-sbc 3743. Proof is therefore unimportant. Contrary to df-sb 2069, this definition makes a substituted formula false when one substitutes a non-existent object for a variable: this is better suited to the "Levy-style" treatment of classes as virtual objects adopted by set.mm. The equality 𝑦 = 𝑥 may seem "reversed", but it is written this way so that "substitution for oneself" does not require symmetry of equality to be seen to be the identity on propositions. (Contributed by BJ, 19-Feb-2026.)

Assertion

Ref	Expression
bj-df-sb	⊢ ([𝐴 / 𝑥]𝜑 ↔ ∃𝑦(𝑦 = 𝐴 ∧ ∀𝑥(𝑦 = 𝑥 → 𝜑)))

Distinct variable groups:   𝑥,𝑦   𝑦,𝐴   𝜑,𝑦

Allowed substitution hints:   𝜑(𝑥)   𝐴(𝑥)

Proof of Theorem bj-df-sb

Step	Hyp	Ref	Expression
1		sbc7 3774	. 2 ⊢ ([𝐴 / 𝑥]𝜑 ↔ ∃𝑦(𝑦 = 𝐴 ∧ [𝑦 / 𝑥]𝜑))
2		sb6 2091	. . . . 5 ⊢ ([𝑦 / 𝑥]𝜑 ↔ ∀𝑥(𝑥 = 𝑦 → 𝜑))
3		sbsbc 3746	. . . . 5 ⊢ ([𝑦 / 𝑥]𝜑 ↔ [𝑦 / 𝑥]𝜑)
4		equcom 2020	. . . . . . 7 ⊢ (𝑥 = 𝑦 ↔ 𝑦 = 𝑥)
5	4	imbi1i 349	. . . . . 6 ⊢ ((𝑥 = 𝑦 → 𝜑) ↔ (𝑦 = 𝑥 → 𝜑))
6	5	albii 1821	. . . . 5 ⊢ (∀𝑥(𝑥 = 𝑦 → 𝜑) ↔ ∀𝑥(𝑦 = 𝑥 → 𝜑))
7	2, 3, 6	3bitr3i 301	. . . 4 ⊢ ([𝑦 / 𝑥]𝜑 ↔ ∀𝑥(𝑦 = 𝑥 → 𝜑))
8	7	anbi2i 624	. . 3 ⊢ ((𝑦 = 𝐴 ∧ [𝑦 / 𝑥]𝜑) ↔ (𝑦 = 𝐴 ∧ ∀𝑥(𝑦 = 𝑥 → 𝜑)))
9	8	exbii 1850	. 2 ⊢ (∃𝑦(𝑦 = 𝐴 ∧ [𝑦 / 𝑥]𝜑) ↔ ∃𝑦(𝑦 = 𝐴 ∧ ∀𝑥(𝑦 = 𝑥 → 𝜑)))
10	1, 9	bitri 275	1 ⊢ ([𝐴 / 𝑥]𝜑 ↔ ∃𝑦(𝑦 = 𝐴 ∧ ∀𝑥(𝑦 = 𝑥 → 𝜑)))

Syntax hints:   → wi 4   ↔ wb 206   ∧ wa 395  ∀wal 1540   = wceq 1542  ∃wex 1781  [wsb 2068  [wsbc 3742

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1912  ax-6 1969  ax-7 2010  ax-8 2116  ax-9 2124  ax-10 2147  ax-12 2185  ax-ext 2709

This theorem depends on definitions:  df-bi 207  df-an 396  df-tru 1545  df-ex 1782  df-nf 1786  df-sb 2069  df-clab 2716  df-cleq 2729  df-clel 2812  df-v 3444  df-sbc 3743

This theorem is referenced by: (None)