Theorem bnj610 34287

Description: Pass from equality (𝑥 = 𝐴) to substitution ([𝐴 / 𝑥]) without the distinct variable condition on 𝐴, 𝑥. (Contributed by Jonathan Ben-Naim, 3-Jun-2011.) (New usage is discouraged.)

Hypotheses

Ref	Expression
bnj610.1	⊢ 𝐴 ∈ V
bnj610.2	⊢ (𝑥 = 𝐴 → (𝜑 ↔ 𝜓))
bnj610.3	⊢ (𝑥 = 𝑦 → (𝜑 ↔ 𝜓′))
bnj610.4	⊢ (𝑦 = 𝐴 → (𝜓′ ↔ 𝜓))

Assertion

Ref	Expression
bnj610	⊢ ([𝐴 / 𝑥]𝜑 ↔ 𝜓)

Distinct variable groups:   𝑦,𝐴   𝜑,𝑦   𝜓,𝑦   𝑥,𝜓′   𝑥,𝑦

Allowed substitution hints:   𝜑(𝑥)   𝜓(𝑥)   𝐴(𝑥)   𝜓′(𝑦)

Proof of Theorem bnj610

Step	Hyp	Ref	Expression
1		vex 3472	. . . 4 ⊢ 𝑦 ∈ V
2		bnj610.3	. . . 4 ⊢ (𝑥 = 𝑦 → (𝜑 ↔ 𝜓′))
3	1, 2	sbcie 3815	. . 3 ⊢ ([𝑦 / 𝑥]𝜑 ↔ 𝜓′)
4	3	sbcbii 3832	. 2 ⊢ ([𝐴 / 𝑦][𝑦 / 𝑥]𝜑 ↔ [𝐴 / 𝑦]𝜓′)
5		sbccow 3795	. 2 ⊢ ([𝐴 / 𝑦][𝑦 / 𝑥]𝜑 ↔ [𝐴 / 𝑥]𝜑)
6		bnj610.1	. . 3 ⊢ 𝐴 ∈ V
7		bnj610.4	. . 3 ⊢ (𝑦 = 𝐴 → (𝜓′ ↔ 𝜓))
8	6, 7	sbcie 3815	. 2 ⊢ ([𝐴 / 𝑦]𝜓′ ↔ 𝜓)
9	4, 5, 8	3bitr3i 301	1 ⊢ ([𝐴 / 𝑥]𝜑 ↔ 𝜓)

Syntax hints:   → wi 4   ↔ wb 205   = wceq 1533   ∈ wcel 2098  Vcvv 3468  [wsbc 3772

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1789  ax-4 1803  ax-5 1905  ax-6 1963  ax-7 2003  ax-8 2100  ax-9 2108  ax-ext 2697

This theorem depends on definitions:  df-bi 206  df-an 396  df-tru 1536  df-ex 1774  df-sb 2060  df-clab 2704  df-cleq 2718  df-clel 2804  df-v 3470  df-sbc 3773

This theorem is referenced by:  bnj611  34458  bnj1000  34481