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| Mirrors > Home > MPE Home > Th. List > Mathboxes > cbvabdavw | Structured version Visualization version GIF version | ||
| Description: Change bound variable in class abstractions. Deduction form. (Contributed by GG, 14-Aug-2025.) |
| Ref | Expression |
|---|---|
| cbvabdavw.1 | ⊢ ((𝜑 ∧ 𝑥 = 𝑦) → (𝜓 ↔ 𝜒)) |
| Ref | Expression |
|---|---|
| cbvabdavw | ⊢ (𝜑 → {𝑥 ∣ 𝜓} = {𝑦 ∣ 𝜒}) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | cbvabdavw.1 | . . . 4 ⊢ ((𝜑 ∧ 𝑥 = 𝑦) → (𝜓 ↔ 𝜒)) | |
| 2 | 1 | cbvsbdavw 36823 | . . 3 ⊢ (𝜑 → ([𝑡 / 𝑥]𝜓 ↔ [𝑡 / 𝑦]𝜒)) |
| 3 | df-clab 2744 | . . 3 ⊢ (𝑡 ∈ {𝑥 ∣ 𝜓} ↔ [𝑡 / 𝑥]𝜓) | |
| 4 | df-clab 2744 | . . 3 ⊢ (𝑡 ∈ {𝑦 ∣ 𝜒} ↔ [𝑡 / 𝑦]𝜒) | |
| 5 | 2, 3, 4 | 3bitr4g 317 | . 2 ⊢ (𝜑 → (𝑡 ∈ {𝑥 ∣ 𝜓} ↔ 𝑡 ∈ {𝑦 ∣ 𝜒})) |
| 6 | 5 | eqrdv 2763 | 1 ⊢ (𝜑 → {𝑥 ∣ 𝜓} = {𝑦 ∣ 𝜒}) |
| Colors of variables: wff setvar class |
| This proof depends on syntax axioms: → wi 4 ↔ wb 209 ∧ wa 401 = wceq 1570 [wsb 2099 ∈ wcel 2146 {cab 2743 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1828 ax-4 1842 ax-5 1943 ax-6 2000 ax-7 2041 ax-9 2156 ax-ext 2737 |
| This proof depends on definitions: df-bi 210 df-an 402 df-ex 1813 df-sb 2100 df-clab 2744 df-cleq 2757 |
| This theorem is used by: cbvsbcdavw 36826 cbvsbcdavw2 36827 cbvrabdavw 36830 cbviotadavw 36838 cbvixpdavw 36847 cbvrabdavw2 36854 cbvixpdavw2 36863 |
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