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| Mirrors > Home > MPE Home > Th. List > Mathboxes > cbvabdavw | Structured version Visualization version GIF version | ||
| Description: Change bound variable in class abstractions. Deduction form. (Contributed by GG, 14-Aug-2025.) |
| Ref | Expression |
|---|---|
| cbvabdavw.1 | ⊢ ((𝜑 ∧ 𝑥 = 𝑦) → (𝜓 ↔ 𝜒)) |
| Ref | Expression |
|---|---|
| cbvabdavw | ⊢ (𝜑 → {𝑥 ∣ 𝜓} = {𝑦 ∣ 𝜒}) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | cbvabdavw.1 | . . . 4 ⊢ ((𝜑 ∧ 𝑥 = 𝑦) → (𝜓 ↔ 𝜒)) | |
| 2 | 1 | cbvsbdavw 37137 | . . 3 ⊢ (𝜑 → ([𝑡 / 𝑥]𝜓 ↔ [𝑡 / 𝑦]𝜒)) |
| 3 | df-clab 2739 | . . 3 ⊢ (𝑡 ∈ {𝑥 ∣ 𝜓} ↔ [𝑡 / 𝑥]𝜓) | |
| 4 | df-clab 2739 | . . 3 ⊢ (𝑡 ∈ {𝑦 ∣ 𝜒} ↔ [𝑡 / 𝑦]𝜒) | |
| 5 | 2, 3, 4 | 3bitr4g 317 | . 2 ⊢ (𝜑 → (𝑡 ∈ {𝑥 ∣ 𝜓} ↔ 𝑡 ∈ {𝑦 ∣ 𝜒})) |
| 6 | 5 | eqrdv 2758 | 1 ⊢ (𝜑 → {𝑥 ∣ 𝜓} = {𝑦 ∣ 𝜒}) |
| Colors of variables: wff setvar class |
| This proof depends on syntax axioms: → wi 4 ↔ wb 209 ∧ wa 401 = wceq 1569 [wsb 2098 ∈ wcel 2144 {cab 2738 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1827 ax-4 1841 ax-5 1942 ax-6 1999 ax-7 2040 ax-9 2154 ax-ext 2732 |
| This proof depends on definitions: df-bi 210 df-an 402 df-ex 1812 df-sb 2099 df-clab 2739 df-cleq 2752 |
| This theorem is used by: cbvsbcdavw 37140 cbvsbcdavw2 37141 cbvrabdavw 37144 cbviotadavw 37152 cbvixpdavw 37161 cbvrabdavw2 37168 cbvixpdavw2 37177 |
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