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Theorem equs5a 2489
Description: A property related to substitution that unlike equs5 2492 does not require a distinctor antecedent. Usage of this theorem is discouraged because it depends on ax-13 2404. This proof uses ax12 2455, see equs5aALT 2398 for an alternative one using ax-12 2215 but not ax13 2407. Usage of the weaker equs5av 2313 is preferred, which uses ax12v2 2217, but not ax-13 2404. (Contributed by NM, 2-Feb-2007.) (New usage is discouraged.)
Assertion
Ref Expression
equs5a (∃𝑥(𝑥 = 𝑦 ∧ ∀𝑦𝜑) → ∀𝑥(𝑥 = 𝑦 → 𝜑))

Proof of Theorem equs5a
StepHypRef Expression
1 nfa1 2190 . 2 Ⅎ𝑥∀𝑥(𝑥 = 𝑦 → 𝜑)
2 ax12 2455 . . 3 (𝑥 = 𝑦 → (∀𝑦𝜑 → ∀𝑥(𝑥 = 𝑦 → 𝜑)))
32imp 412 . 2 ((𝑥 = 𝑦 ∧ ∀𝑦𝜑) → ∀𝑥(𝑥 = 𝑦 → 𝜑))
41, 3exlimi 2256 1 (∃𝑥(𝑥 = 𝑦 ∧ ∀𝑦𝜑) → ∀𝑥(𝑥 = 𝑦 → 𝜑))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ∧ wa 401  ∀wal 1567  ∃wex 1811
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1944  ax-6 2001  ax-7 2042  ax-10 2179  ax-12 2215  ax-13 2404
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-ex 1812  df-nf 1816
This theorem is used by:  equs45f  2491
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