Theorem exbiriVD 45280

Description: Virtual deduction proof of exbiri 811. The following user's proof is completed by invoking mmj2's unify command and using mmj2's StepSelector to pick all remaining steps of the Metamath proof.

h1::	⊢ ((𝜑 ∧ 𝜓) → (𝜒 ↔ 𝜃))
2::	⊢ (   𝜑   ▶   𝜑   )
3::	⊢ (   𝜑   ,   𝜓   ▶   𝜓   )
4::	⊢ (   𝜑   ,   𝜓   ,   𝜃   ▶   𝜃   )
5:2,1,?: e10 45121	⊢ (   𝜑   ▶   (𝜓 → (𝜒 ↔ 𝜃))   )
6:3,5,?: e21 45156	⊢ (   𝜑   ,   𝜓   ▶   (𝜒 ↔ 𝜃)   )
7:4,6,?: e32 45184	⊢ (   𝜑   ,   𝜓   ,   𝜃   ▶   𝜒   )
8:7:	⊢ (   𝜑   ,   𝜓   ▶   (𝜃 → 𝜒)   )
9:8:	⊢ (   𝜑   ▶   (𝜓 → (𝜃 → 𝜒))   )
qed:9:	⊢ (𝜑 → (𝜓 → (𝜃 → 𝜒)))

(Contributed by Alan Sare, 31-Dec-2011.) (Proof modification is discouraged.) (New usage is discouraged.)

Hypothesis

Ref	Expression
exbiriVD.1	⊢ ((𝜑 ∧ 𝜓) → (𝜒 ↔ 𝜃))

Assertion

Ref	Expression
exbiriVD	⊢ (𝜑 → (𝜓 → (𝜃 → 𝜒)))

Proof of Theorem exbiriVD

Step	Hyp	Ref	Expression
1		idn3 45042	. . . . 5 ⊢ (   𝜑   ,   𝜓   ,   𝜃   ▶   𝜃   )
2		idn2 45040	. . . . . 6 ⊢ (   𝜑   ,   𝜓   ▶   𝜓   )
3		idn1 45001	. . . . . . 7 ⊢ (   𝜑   ▶   𝜑   )
4		exbiriVD.1	. . . . . . 7 ⊢ ((𝜑 ∧ 𝜓) → (𝜒 ↔ 𝜃))
5		pm3.3 448	. . . . . . . 8 ⊢ (((𝜑 ∧ 𝜓) → (𝜒 ↔ 𝜃)) → (𝜑 → (𝜓 → (𝜒 ↔ 𝜃))))
6	5	com12 32	. . . . . . 7 ⊢ (𝜑 → (((𝜑 ∧ 𝜓) → (𝜒 ↔ 𝜃)) → (𝜓 → (𝜒 ↔ 𝜃))))
7	3, 4, 6	e10 45121	. . . . . 6 ⊢ (   𝜑   ▶   (𝜓 → (𝜒 ↔ 𝜃))   )
8		pm2.27 42	. . . . . 6 ⊢ (𝜓 → ((𝜓 → (𝜒 ↔ 𝜃)) → (𝜒 ↔ 𝜃)))
9	2, 7, 8	e21 45156	. . . . 5 ⊢ (   𝜑   ,   𝜓   ▶   (𝜒 ↔ 𝜃)   )
10		biimpr 220	. . . . . 6 ⊢ ((𝜒 ↔ 𝜃) → (𝜃 → 𝜒))
11	10	com12 32	. . . . 5 ⊢ (𝜃 → ((𝜒 ↔ 𝜃) → 𝜒))
12	1, 9, 11	e32 45184	. . . 4 ⊢ (   𝜑   ,   𝜓   ,   𝜃   ▶   𝜒   )
13	12	in3 45036	. . 3 ⊢ (   𝜑   ,   𝜓   ▶   (𝜃 → 𝜒)   )
14	13	in2 45032	. 2 ⊢ (   𝜑   ▶   (𝜓 → (𝜃 → 𝜒))   )
15	14	in1 44998	1 ⊢ (𝜑 → (𝜓 → (𝜃 → 𝜒)))

Syntax hints:   → wi 4   ↔ wb 206   ∧ wa 395

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 207  df-an 396  df-3an 1089  df-vd1 44997  df-vd2 45005  df-vd3 45017

This theorem is referenced by: (None)