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Theorem rspsbc2VD 45931
Description: Virtual deduction proof of rspsbc2 45611. The following user's proof is completed by invoking mmj2's unify command and using mmj2's StepSelector to pick all remaining steps of the Metamath proof.
1:: (   𝐴 ∈ 𝐵   ▶   𝐴 ∈ 𝐵   )
2:: (   𝐴 ∈ 𝐵   ,   𝐶 ∈ 𝐷   ▶   𝐶 ∈ 𝐷   )
3:: (   𝐴 ∈ 𝐵   ,   𝐶 ∈ 𝐷   ,   ∀𝑥 ∈ 𝐵 ∀𝑦 ∈ 𝐷𝜑   ▶   ∀𝑥 ∈ 𝐵∀𝑦 ∈ 𝐷𝜑   )
4:1,3,?: e13 45824 (   𝐴 ∈ 𝐵   ,   𝐶 ∈ 𝐷   ,   ∀𝑥 ∈ 𝐵 ∀𝑦 ∈ 𝐷𝜑   ▶   [𝐴 / 𝑥]∀𝑦 ∈ 𝐷𝜑   )
5:1,4,?: e13 45824 (   𝐴 ∈ 𝐵   ,   𝐶 ∈ 𝐷   ,   ∀𝑥 ∈ 𝐵 ∀𝑦 ∈ 𝐷𝜑   ▶   ∀𝑦 ∈ 𝐷[𝐴 / 𝑥]𝜑   )
6:2,5,?: e23 45831 (   𝐴 ∈ 𝐵   ,   𝐶 ∈ 𝐷   ,   ∀𝑥 ∈ 𝐵 ∀𝑦 ∈ 𝐷𝜑   ▶   [𝐶 / 𝑦][𝐴 / 𝑥]𝜑   )
7:6: (   𝐴 ∈ 𝐵   ,   𝐶 ∈ 𝐷   ▶   (∀𝑥 ∈ 𝐵 ∀𝑦 ∈ 𝐷𝜑 → [𝐶 / 𝑦][𝐴 / 𝑥]𝜑)   )
8:7: (   𝐴 ∈ 𝐵   ▶   (𝐶 ∈ 𝐷 → (∀𝑥 ∈ 𝐵∀𝑦 ∈ 𝐷𝜑 → [𝐶 / 𝑦][𝐴 / 𝑥]𝜑))   )
qed:8: (𝐴 ∈ 𝐵 → (𝐶 ∈ 𝐷 → (∀𝑥 ∈ 𝐵∀𝑦 ∈ 𝐷𝜑 → [𝐶 / 𝑦][𝐴 / 𝑥]𝜑)))
(Contributed by Alan Sare, 31-Dec-2011.) (Proof modification is discouraged.) (New usage is discouraged.)
Assertion
Ref Expression
rspsbc2VD (𝐴 ∈ 𝐵 → (𝐶 ∈ 𝐷 → (∀𝑥 ∈ 𝐵 ∀𝑦 ∈ 𝐷 𝜑 → [𝐶 / 𝑦][𝐴 / 𝑥]𝜑)))
Distinct variable groups:   𝑦,𝐴   𝑥,𝐵   𝑥,𝐷,𝑦
Allowed substitution hints:   𝜑(𝑥, 𝑦)   𝐴(𝑥)   𝐵(𝑦)   𝐶(𝑥, 𝑦)

Proof of Theorem rspsbc2VD
StepHypRef Expression
1 idn2 45690 . . . . 5 (   𝐴 ∈ 𝐵   ,   𝐶 ∈ 𝐷   ▶   𝐶 ∈ 𝐷   )
2 idn1 45651 . . . . . 6 (   𝐴 ∈ 𝐵   ▶   𝐴 ∈ 𝐵   )
3 idn3 45692 . . . . . . 7 (   𝐴 ∈ 𝐵   ,   𝐶 ∈ 𝐷   ,   ∀𝑥 ∈ 𝐵 ∀𝑦 ∈ 𝐷 𝜑   ▶   ∀𝑥 ∈ 𝐵 ∀𝑦 ∈ 𝐷 𝜑   )
4 rspsbc 3825 . . . . . . 7 (𝐴 ∈ 𝐵 → (∀𝑥 ∈ 𝐵 ∀𝑦 ∈ 𝐷 𝜑 → [𝐴 / 𝑥]∀𝑦 ∈ 𝐷 𝜑))
52, 3, 4e13 45824 . . . . . 6 (   𝐴 ∈ 𝐵   ,   𝐶 ∈ 𝐷   ,   ∀𝑥 ∈ 𝐵 ∀𝑦 ∈ 𝐷 𝜑   ▶   [𝐴 / 𝑥]∀𝑦 ∈ 𝐷 𝜑   )
6 sbcralg 3820 . . . . . . 7 (𝐴 ∈ 𝐵 → ([𝐴 / 𝑥]∀𝑦 ∈ 𝐷 𝜑 ↔ ∀𝑦 ∈ 𝐷 [𝐴 / 𝑥]𝜑))
76biimpd 232 . . . . . 6 (𝐴 ∈ 𝐵 → ([𝐴 / 𝑥]∀𝑦 ∈ 𝐷 𝜑 → ∀𝑦 ∈ 𝐷 [𝐴 / 𝑥]𝜑))
82, 5, 7e13 45824 . . . . 5 (   𝐴 ∈ 𝐵   ,   𝐶 ∈ 𝐷   ,   ∀𝑥 ∈ 𝐵 ∀𝑦 ∈ 𝐷 𝜑   ▶   ∀𝑦 ∈ 𝐷 [𝐴 / 𝑥]𝜑   )
9 rspsbc 3825 . . . . 5 (𝐶 ∈ 𝐷 → (∀𝑦 ∈ 𝐷 [𝐴 / 𝑥]𝜑 → [𝐶 / 𝑦][𝐴 / 𝑥]𝜑))
101, 8, 9e23 45831 . . . 4 (   𝐴 ∈ 𝐵   ,   𝐶 ∈ 𝐷   ,   ∀𝑥 ∈ 𝐵 ∀𝑦 ∈ 𝐷 𝜑   ▶   [𝐶 / 𝑦][𝐴 / 𝑥]𝜑   )
1110in3 45686 . . 3 (   𝐴 ∈ 𝐵   ,   𝐶 ∈ 𝐷   ▶   (∀𝑥 ∈ 𝐵 ∀𝑦 ∈ 𝐷 𝜑 → [𝐶 / 𝑦][𝐴 / 𝑥]𝜑)   )
1211in2 45682 . 2 (   𝐴 ∈ 𝐵   ▶   (𝐶 ∈ 𝐷 → (∀𝑥 ∈ 𝐵 ∀𝑦 ∈ 𝐷 𝜑 → [𝐶 / 𝑦][𝐴 / 𝑥]𝜑))   )
1312in1 45648 1 (𝐴 ∈ 𝐵 → (𝐶 ∈ 𝐷 → (∀𝑥 ∈ 𝐵 ∀𝑦 ∈ 𝐷 𝜑 → [𝐶 / 𝑦][𝐴 / 𝑥]𝜑)))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ∈ wcel 2144  ∀wral 3076  [wsbc 3738
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-10 2177  ax-11 2193  ax-12 2212  ax-ext 2732
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1572  df-ex 1812  df-nf 1816  df-sb 2099  df-clab 2739  df-cleq 2752  df-clel 2835  df-nfc 2909  df-ral 3077  df-v 3452  df-sbc 3739  df-vd1 45647  df-vd2 45655  df-vd3 45667
This theorem is used by: (None)
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